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3 years ago

X + (x + 11) =79 solve x

Mathematics

2 answers:

posledela3 years ago

6 0

Answer:

x=34

Step-by-step explanation:

x + (x + 11) =79

Combine like terms

2x+11 = 79

Subtract 11 from each side

2x+11-11 = 79-11

2x = 68

Divide by 2

2x/2 = 68/2

x = 34

PilotLPTM [1.2K]3 years ago

3 0

Answer:

$\Huge \boxed{x=34}$

$\rule[225]{225}{2}$

Step-by-step explanation:

$x+x+11=79$

Combining like terms.

$2x+11=79$

Subtracting 11 from both sides.

$2x=68$

Dividing both sides by 2.

$x=34$

$\rule[225]{225}{2}$

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The measures of the angles of Δ DEF are 36° , 72° , 72°

Step-by-step explanation:

The sum of the measures of the interior angles in any triangle is 180°

In Δ DEF

The ratio between the measures of its interior angles is 2 : 4 : 4

To find the measure of each angle

1. Find the sum of the ratio between the measures of its angles

2. Divide 180° by the sum of the ratio

3. Multiply the quotient by each ratio

∵ The ratio between the measures of the angles of Δ DEF = 2 : 4 : 4

∴ The sum of the ratio = 2 + 4 + 4 = 10

→ m∠D : m∠E : m∠F : sum of the ratio

→ 2 : 4 : 4 : 10

→ ? : ? : ? : 180°

Divide 180 by 10, then multiply the quotient by the components of

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∵ m∠D = $(2)\frac{180}{10}$

∴ m∠D = 36°

∵ m∠E = $(4)\frac{180}{10}$

∴ m∠D = 72°

∵ m∠F = $(4)\frac{180}{10}$

∴ m∠F = 72°

The measures of the angles of Δ DEF are 36° , 72° , 72°

Learn more:

You can learn more about the ratio in brainly.com/question/2707032

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Terry and Callie do word processing. For a certain prospectus Callie can prepare it two hours faster than Terry can. If they wor

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Time taken by callie alone is 8.1 hours

Solution:

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Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is $\frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }$

If they work together they can do the entire prospectus in five hours

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On cross-multiplication we get,

$\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}$

$\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}$

On cross multiplication ,we get

$\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}$

using quadratic formula:-

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$x=\frac{12 \pm \sqrt{144-40}}{2}$

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Let us take a = 10.1

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Answer:

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Step-by-step explanation:

Plane A and B start out 615 feet apart, and we find this by subtracting the height of plane A from plane B, getting 5000-4385=615. Now we have to find how many more feet of altitude plane A is gaining per second over plane B.

To find this we subtract 45.25 from 55.5 and get 10.25 feet per second. Now to find out how many seconds until they'll be at the same altitude we simply divide 615 by 10.25, getting 60 seconds.

For the second part, to find the altitude at this point, we simply multiply the altitude gain of one of the planes per second by the time of 60 seconds to get how much altitude they gained over that time, and add it to the starting altitude. Doing this with plane B we get 45.25*60=2715, and we add that to 5000 to get the final answer of 7715.

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