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taurus [48]
3 years ago
11

X + (x + 11) =79 solve x

Mathematics
2 answers:
posledela3 years ago
6 0

Answer:

x=34

Step-by-step explanation:

x + (x + 11) =79

Combine like terms

2x+11 = 79

Subtract 11 from each side

2x+11-11 = 79-11

2x = 68

Divide by 2

2x/2 = 68/2

x = 34

PilotLPTM [1.2K]3 years ago
3 0

Answer:

\Huge \boxed{x=34}

\rule[225]{225}{2}

Step-by-step explanation:

x+x+11=79

Combining like terms.

2x+11=79

Subtracting 11 from both sides.

2x=68

Dividing both sides by 2.

x=34

\rule[225]{225}{2}

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the number 1 through 10 are written on individual cards and placed in a bag. if you reach into the bag and pull out a card, what
ratelena [41]

1/10 because there are 10 cards and only one 7


6 0
3 years ago
Elias has decided to fence in a garden that is in the shape of a parallelogram. If one side measures 76 ft and 250 ft of fencing
Leni [432]

The length of side of garden are 76 feet and 49 feet

<em><u>Solution:</u></em>

Given that, Elias has decided to fence in a garden that is in the shape of a parallelogram

Measure of one side = 76 feet

250 ft of fencing is needed to enclose the garden

Therefore, perimeter = 250

<em><u>The perimeter of parallelogram is given by:</u></em>

Perimeter = 2(a + b)

Where, a and b are the length of sides

Here, a = 76

b = ?

<em><u>Substituting in formula, we get</u></em>

250 = 2(76 + b)

250 = 152 + b

2b = 250 - 152

2b = 98

b = 49

Thus the length of side of garden is 49 feet

8 0
2 years ago
The following diagram shows parallel lines cut be a transversal. What is the measure of Angle 2?
Crank
2x + 100 = 5x + 55
3x = 45
x = 15

2(15) + 100 = 130

180-130 = 50

so angle 2 is 50 degrees

3 0
3 years ago
Problem<br> How many numbers between 111 and 100100100 (inclusive) are divisible by 101010 or 777?
olga2289 [7]

I suspect you meant

"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"

• Count the multiples of 10:

⌊100/10⌋ = ⌊10⌋ = 10

• Count the multiples of 7:

⌊100/7⌋ ≈ ⌊14.2857⌋ = 14

• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and

⌊100/70⌋ ≈ ⌊1.42857⌋ = 1

(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)

Then using the inclusion/exclusion principle, there are

10 + 14 - 1 = 23

numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.

6 0
2 years ago
You have four cards, labeled 2-5. What is the probability of drawing a number less than 3, putting the card back, then drawing a
Usimov [2.4K]

|\Omega|=4^2=16\\ |A|=1\cdot 3=3\\\\ P(A)=\dfrac{3}{16}\approx19\%

3 0
3 years ago
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