4. Since f(x) = 2x - 1, we are looking for h(2x - 1), which is (2x-1)^2 + 1. By tha time you expand this you'll get, 4x^2 - 4x + 2. So that is the answer.
5. f(f(x)) = f(2x - 1) = 2(2x - 1) - 1 = 4x - 3
6. h(g(x)) = h(3x) = (3x)^2 + 1 = 9x^2 + 1
Check the picture below.
let's recall that once we move an angle in the opposite direction of the 0-line or x-axis, we end up with a negative counterpart angle.
since we know that θ is on the IV Quadrant, then its negative counterpart must be across the line, and tangent is negative on the IV Quadrant, and positive on the I Quadrant.
Answer:
your answer in ☝️ this photo
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Answer:
12x^18
Step-by-step explanation: