Which of the following functions satisfies these two characteristics: f(1/2) = 0, f(2) = π
1 answer:
Answer:
c
Step-by-step explanation:
Only f(x) = π cos(πx) accounts for the correct results.
To varify, you need to substitute x for the value given in f(x).
f(1/2) = π cos(π * 1/2) and this result is 0
simularly...
f(2) = π cos(π * 2) and this result is π
So answer c is correct.
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A' =( -1,-4 )
B' = ( 3,-2 )
C'=( - 2, 2 )