A force has to have which two Factors

A fish tank measures 0.40 meter long by 0.20 meter wide by 0.30 meter high. What is the width of the tank in centimeters?

umka21 [38]

Well the width is 0.20 meters. Since there are a hundred centimeters in a meter, we just have to move the decimal point two times to the right to get a 20 centimeter width.

6 0

3 years ago

A chemist fills a reaction vessel with 7.92 atm nitrogen (N2) gas, 2.02 atm hydrogen (H2) gas, and 2.11 atm ammonia (NH3) gas at

djverab [1.8K]

<u>Answer:</u> The Gibbs free energy of the given reaction is -40 kJ

<u>Explanation:</u>

The given chemical equation follows:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

The equation for the standard Gibbs free change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(NH_3(g))})]-[(1\times \Delta G^o_f_{(N_2(g))})+(3\times \Delta G^o_f_{(H_2(g))})]$

We are given:

$\Delta G^o_f_{(NH_3(l))}=-16.45kJ/mol\\\Delta G^o_f_{(H_2(g))}=0kJ/mol\\\Delta G^o_f_{(N_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-16.45))]-[(1\times (0))+(3\times (0))]\\\\\Delta G^o_{rxn}=-32.9kJ/mol$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln Q_{eq}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = -32.9 kJ/mol = -32900 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = Temperature = $25^oC=[273+25]K=298K$

$Q_{eq}$ = Ratio of concentration of products and reactants at any time = $\frac{(p_{NH_3})^2}{(p_{H_2})^3\times p_{N_2}}$

$p_{NH_3}=2.11atm$

$p_{N_2}=7.92atm$

$p_{H_2}=2.02atm$

Putting values in above equation, we get:

$\Delta G=-32900J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(2.11)^2}{(2.02)^3\times 7.92}))\\\\\Delta G=-39553.04J/mol=--39.55kJ=-40kJ$

Hence, the Gibbs free energy of the given reaction is -40 kJ

7 0

3 years ago

How many moles of atoms are there in 27g of aluminium

Marrrta [24]

We know that the molar mass of Al is 27 g/mol.

27 g Al* (1 mol Al/ 27 g Al)= 1 mol Al.

The final answer is 1 mol Al~

4 0

4 years ago

Write a balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution. Be sure to add ph

Serhud [2]

Answer:

The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

$Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

Explanation:

The reaction :

$Cr_2O_7^{2-}\rightarrow Cr^{3+}$

Balancing of reaction in an acidic medium:

Step 1: Balance the atoms in the reaction:

$Cr_2O_7^{2-}(aq)\rightarrow 2Cr^{3+}(aq)$

Step 2: Balance oxygen atom by adding water on the side where no oxygen or less oxygen atom is present;

$Cr_2O_7^{2-}(aq)\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

Step 3: Balance the hydrogen atom by adding hydrogen ions on the side where water is absent:

$Cr_2O_7^{2-}(aq)+14H^+(aq)\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

Step 4: Now balance charge by adding electrons on the side where more positive charge is present

$Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

$Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

6 0

3 years ago

Which of these is a balanced chemical equation?

Alex777 [14]

I believe its G because it has the same amount of particles. (I haven't had much background)

3 0

4 years ago

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