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IgorC [24]
3 years ago
12

What is 977 divided by 44

Mathematics
2 answers:
valentinak56 [21]3 years ago
4 0

The answer is: 22.204545...

givi [52]3 years ago
3 0
The answer is 22.2045454545
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What are the solution(s) to the quadratic equation x² - 25 = 0?
gtnhenbr [62]

Answer:

x = ±5

Step-by-step explanation:

x² - 25 = 0

x² = 25

√x² = √25

x = ±5

Check:

5² - 25 = 0

-5² - 25 = 0

25 - 25 = 0

4 0
1 year ago
What decimal is equivalent to each fraction?
Maksim231197 [3]
1/6 = 0.16 with a line over the 6 because it is repeating
3 0
3 years ago
sal works for a computer repair shop. he has determines that customers pay on average $150 for each computer they bring in. He p
Effectus [21]

Answer:

The answer is :

sal must repair 320 computers in a year to break even.

Step-by-step explanation:

The break even point in a business is the point at which the total costs and the total revenue in a business are equal.

In order to calculate sal's break even point, we will first of all calculate the total costs incurred during the business year, then using the selling price (repairing price), we will calculate how many computers will be repaired to reach the incurred cost. This is done as follows:

Rent per month = $2,000

∴ Rent for a year (12 months) = 2,000 × 12 = $2,400

Cost incurred in fixing each computer = $75

Priced charged for fixing each computer = $150

Next, since we know that sal requires $75 in parts and labor to fix a computer, we will calculate the net price charged for each computer fixed as follows:

Net price charged = Priced charged for fixing each computer - Cost incurred in fixing each computer

Net price charged = 150 - 75 = $75

Finally to calculate the break even point, we know the net income (net price charged) for each computer and the costs of rent for each year, therefore, we will divide the cost incurred by the net price charged, as follows:

break even point = cost of rent for one year ÷ net price charged

break even point = 24,000 ÷ 75 = 320 computers.

Therefore, by the time sal repairs 320 computers during the year, he must have covered the costs incurred in operations, every additional repair, becomes a profit.

3 0
3 years ago
Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
3 years ago
Let event A = You roll an even number on the first cube.Let event B = You roll a 6 on the second cube.Are the events independent
Gnesinka [82]

The events are independent. By definition, it means that knowledge about one event does not help you predict the second, and this is the case: even if you knew that you rolled an even number on the first cube, would you be more or less confident about rolling a six on the second? No.

An example in which two events about rolling cubes are dependent could be something like:

Event A: You roll the first cube

Event B: The second cube returns a higher number than the first one.

In this case, knowledge on event A does change you view on event B (and vice versa): if you know that you rolled a 6 on the first cube you don't want to bet on event B, while if you know that you rolled a 1 on the first cube, you're certain that event B will happen.

Conversely, if you know that event B has happened, you are more likely to think that the first cube rolled a small number, and vice versa.


8 0
3 years ago
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