Answer: 0.05
Step-by-step explanation:
Let M = Event of getting an A in Marketing class.
S = Event of getting an A in Spanish class,
i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45
Required probability = P(neither M nor S)
= P(M'∩S')
= P(M∪S)' [∵P(A'∩B')=P(A∪B)']
=1- P(M∪S) [∵P(A')=1-P(A)]
= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]
= 1- (0.80+0.60-0.45)
= 1- 0.95
= 0.05
hence, the probability that Helen does not get an A in either class= 0.05
Answer:DanGrjdhbcGoKghryinjvgjcy
Step-by-step explanation:
1,045 to the nearest thousands would be <u>1,000</u> because you must round down since there are no numbers close enough to round up.
Answer:
a
The probability that the selected joint was judged to be defective by neither of the two inspectors is
b
The probability that the selected joint was judged to be defective by inspector B but not by inspector A is
Step-by-step explanation:
From the question we are told that
The sample size is
The number of outcome for inspector A is
The number of outcome for inspector B is
The number of joints judged defective by both inspector is
The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as
Now
substituting values
So
the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as
Now
substituting values
So
Answer:
the answer is a
Step-by-step explanation:
if you compare pm and qn pm is shorter so you see its only a little bit longer then that so its close to there.