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Brilliant_brown [7]
3 years ago
8

A linear function includes the ordered pairs (0, 1), (3, 3), and (9, n). What is the value of n?

Mathematics
1 answer:
alexgriva [62]3 years ago
8 0
The answer is A I think
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Kevin is 4 times as old as Daniel and is also 6 years older than Daniel
MAXImum [283]

Answer:

Part a) Daniel's age is 2 years

Part b) Kevin's age is 8 years

Step-by-step explanation:

<u><em>The question is </em></u>

Part a) How old is Daniel?

Part b) How old is Kevin?

Let

x ----> Kevin's age

y ----> Daniel's age

we know that

x=4y-----> equation A

x=y+6 ----> equation B

Equate equation A and equation B

4y=y+6

solve for y

4y-y=6

3y=6

y=2

therefore

Daniel's age is 2 years

<em>Find the value of x</em>

substitute the value of y in any of the two equations

x=4(2)=8\ years

x=2+6=8\ years

therefore

Kevin's age is 8 years

6 0
3 years ago
What is the area of this triangle
Misha Larkins [42]

Answer:

Probably b or e

Step-by-step explanation:

this took me a while to answer this.

4 0
3 years ago
Christine went shopping and bought each of her eighteight nephews a​ gift, either a video costing​ $14.95 or a CD costing​ $16.8
pogonyaev
So I think you should set up an equation like this: 14.95x+16.88y=131.18 , x+y=8

so x=8-y, plug this into the original equation:
14.95(8-y)+16.88y=131.18
Evaluate: 119.60-14.95y+16.88y=131.18
Combine like terms: 119.60+1.93y=131.18
Subtract 119.60 from both sides. You get: 1.93y=11.58
Divide both sides by 1.93. You get y=6

Plug into second equation: x+y=8 ---> x+6=8 and solve for x. x=2

Christine bought 2 video games and 6 CDs. 14.95(2)+16.88(6)=131.18
4 0
3 years ago
What is four and five eighths as a improper fraction and a mixed number
Afina-wow [57]
4 5/8 as an improper fraction is 37/8
——> 8*4=32 32+5=37
As a mixed number it is the same I think. 5 can’t decide into 8 so it stays 4 5/8.

Hopefully this helps...
5 0
3 years ago
In a bag of 100 marbles comprised of many colors, 25 are blue. suppose marbles are selected at random.
satela [25.4K]

Solution: The number of ways we can arrange 3 blue marbles if a set of 5 marbles is selected is:

\binom{5}{3}=\frac{5!}{(5-3)!3!}

                          =\frac{120}{2 \times 6}

                          =\frac{120}{12}=10

Therefore, there are 10 ways we could arrange 3 blue marbles.

3 0
3 years ago
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