Find the area of the 5 sides (not 6 because the top is open).
The area is made up of a load of rectangles. 2 of each rectangle are present except the top and bottom.
(4 x 2 x 2) + (3 x 2 x 2) + (3 x 4) = 40yd²
Answer:
4x+88=180
First angle is 54°
Second angle is 23°
Third angle is 103°
Step-by-step explanation:
Let x be the second angle. First angle is 31+x. Third angle is 2*(31+x)-5 = 62+2x-5 = 2x+57
All angles in a triangle add upto 180°
31+x+x+2x+57 = 180
4x+88=180
Subtract 88 from both sides,
4x = 92
Divide by 4,
x = 23°
31+x = 54°
2x+57 = 2*23 + 57 = 46+57 = 103°
The equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S
To answer the question, we need to know what an equation is
<h3>What is an equation?</h3>
An equation is a mathematical expression that show the relationship between two variables.
Given 9cos(sin¯¹(x)) = √(81 – 81x²), we need to show L.H.S = R.H.S
So, L.H.S = 9cos(sin¯¹(x))
= 9[√{1 - sin²(sin¯¹(x)}] (Since sin²y + cos²y = 1 ⇒ cosy = √[1 - sin²y])
9[√{1 - sin²(sin¯¹(x)}] = √9² × √{1 - sin²(sin¯¹(x)}]
= √[9² × {1 - sin²(sin¯¹(x)}]
= √[81 × {1 - sin²(sin¯¹(x)}]
= √[81 × {1 - x²}] (since sin²(sin¯¹(x) = [sin(sin¯¹(x)]² = x²)
= √(81 – 81x²)
= R.H.S
So, the equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S
Learn more about equations here:
brainly.com/question/2888445
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Answer:
oki
Step-by-step explanation:
I will help people get points!
