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Marizza181 [45]
3 years ago
12

Zoe wanted to make 8 brackets but was short 115 beads

Mathematics
1 answer:
Goshia [24]3 years ago
7 0

Answer:

what is the rest of the qustion

Step-by-step explanation:

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Someone help me out please
uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\   (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4.

2 step (A): simplify to obtain the final radical term on one side of the equation.

-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2.

3 step (F): raise both sides of the equation to the power of 2 again.

(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2.

4 step (E): simplify to get a quadratic equation.

4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0.

5 step (D): use the quadratic formula to find the values of x.

D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}.

6 step (C): apply the zero product rule.

x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}.

Additional 7 step: check these solutions, substituting into the initial equation.

3 0
3 years ago
If a board game was originally $25 and it was on sale for $18 what is the percent of discount
fredd [130]
The percent of the discount is 28 percent off
4 0
3 years ago
HELP ASAP!
kolezko [41]

Because vertical angles always equal each other. linear pairs always equals 180 degrees always. hope this helps :)

8 0
3 years ago
A fair coin is tossed four times. What is the probability that the number of heads appearing on the first two tosses is equal to
alekssr [168]

Answer: 3/8

Step-by-step explanation:

Since it is a fair coin, then generally, P(Head) = P(Tail) = ½

And since we've been asked to find the probability that the number of heads in the first two tosses be equal to the number of heads in the second two tosses, tossing a fair coin four times, the possible outcomes of having equal number of heads in first two tosses and second two tosses becomes:

[HHHH] or [HTHT] or [THTH] or [TTTT] or [HTTH] or [THHT]

=[½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½]

=1/16 * 6

=6/16

=3/8.

8 0
3 years ago
Can someone please help me with this question?
liq [111]
To get the solution we are looking for we need to point out what we know.
1. We assume that 55 is 100% because its the output value of the task.
2. We assume that the x is the value we are looking for. 
3. If 100% = 55 so we can write it down as 100%=55 
4. We know that x% = 44 of the output value so we can write it as x%=44.
5. Now we have two simple equations: 1) 100%=55 2) x%=44 where left sides of both of them have the same units and both right sides have the same units so we can do something like that 100%/x%=55/44.
6. Now we just have to solve the simple equation and we will get the answer.
7. Solution for 44 is what percent of 55 100%/x%=55/44 (100/x)*x=(55/44)*x we multiply both sides of the equation by x 100= 1.25*x we divide both sides of the equation by (1.25) to get x 100/1.25=x 80=x now we have: 44 is 80% of 55! 

Quick answer = 44 is 80% of 55
Hope this helps! ;D
3 0
3 years ago
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