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11111nata11111 [884]
3 years ago
5

Hi I need help with this, I am very confused

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

1/81

Step-by-step explanation:

P(1st ticket is a winner) = 1/9

These are independent events

P(2nd ticket is a winner) = 1/9

P (winner, winner) = 1/9 * 1/9 = 1/81

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!!!!!Help!!!!
Alja [10]
The correct answer is y=-13/10x+13 as it matches the graph

Hope this helped :)
7 0
3 years ago
If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.
zmey [24]

Answer:

a=3 and b=5.

Step-by-step explanation:

So I believe the problem is this:

\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}

where we are asked to find values for a and b such that the equation holds for any x in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)

2(4x+3)=a(x+7)+b(x-3)

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

2(4\cdot -7+3)=a(-7+7)+b(-7-3)

2(-28+3)=a(0)+b(-10)

2(-25)=0-10b

-50=-10b

Divide both sides by -10:

\frac{-50}{-10}=b

5=b

Now we have:

2(4x+3)=a(x+7)+b(x-3) with b=5

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

2(4\cdot 3+3)=a(3+7)+b(3-3)

2(12+3)=a(10)+b(0)

2(15)=10a+0

30=10a

Divide both sides by 10:

\frac{30}{10}=a

3=a

So a=3 and b=5.

4 0
3 years ago
Read 2 more answers
Name three synonyms for "Solution": _____________,___________,______________
Damm [24]

Answer:

1 quick fix            2 solving               3 result

Step-by-step explanation:

hope it helps

6 0
2 years ago
URGENT PLZ HELP ME!!!
hichkok12 [17]

Answer:

You would click at (0,-7)

Step-by-step explanation:

Definition of the minimum point:

"The minimum value of a function is the place where the graph has a vertex at its lowest point. In the real world, you can use the minimum value of a quadratic function to determine minimum cost or area."

Although this is not a quadratic, it still has a minimum point.

The minimum point here would be at it's lowest point

The minimum/lowest point is (0,-7)

4 0
2 years ago
What is the equation of the line that passes through the points (3,-2) and (6,3)?
cupoosta [38]

Answer: m=5/3

Step-by-step explanation:

i think its right

4 0
3 years ago
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