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3 years ago

2sec^2x - secx - 1 = 0

1 answer:

8 0

What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0

Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1

I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!

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Find a potential function for F or determine that F is not conservative. (If F is not conservative, enter NOT CONSERVATIVE.) F =

xxMikexx [17]

For $F$ to be conservative, we need to have

$\dfrac{\partial f}{\partial x}=\cos z$

$\dfrac{\partial f}{\partial y}=10y$

$\dfrac{\partial f}{\partial z}=-x\sin z$

Integrate the first PDE with respect to $x$ :

$\displaystyle\int\frac{\partial f}{\partial x}\,\mathrm dx+\int\cos z\,\mathrm dx\implies f(x,y,z)=x\cos z+g(y,z)$

Differentiate with respect to $y$ :

$\dfrac{\partial f}{\partial y}=10y=\dfrac{\partial g}{\partial y}\implies g(y,z)=5y^2+h(z)$

Now differentiate $f$ with respect to $z$ :

$\dfrac{\partial f}{\partial z}=-x\sin z=-x\sin z+\dfrac{\mathrm dh}{\mathrm dz}\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

So we have

$f(x,y,z)=x\cos z+5y^2+C$

so $F$ is indeed conservative.

8 0

3 years ago

Mark values his drum set at $800 and ella values her guitar at $1,000. suppose that mark trades his drum set for ella's guitar.

Novosadov [1.4K]

If they made this trade, it would make sense that Mark would also have to give Ella $200. This is because the difference in value is that amount in the favor of Ella. You can see that by subtracting the two values from each other.

$1000 - $800 = $200

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3 years ago

I need help with this

Arturiano [62]

Answer:

Bc,AB,Ac

Step-by-step explanation:

Bc because

Bc is 150

Ab is 150

Ac is 100

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