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Serhud [2]
3 years ago
14

2sec^2x - secx - 1 = 0

Mathematics
1 answer:
Ivenika [448]3 years ago
8 0
What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0


Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1


I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
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anzhelika [568]

Answer:

\fbox{\begin{minipage}{3.5em}338 (ft)\end{minipage}}

Step-by-step explanation:

The problem could be simplified as following:

Given:

The radius of a circle O is 26 feet.

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Step 2: Let's put the data into formula to work out the length L of arc:

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Hope this helps!

:)

7 0
3 years ago
Hurry please <br><br> What is the rule for the reflection?
Crank

Answer:

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x). the line y = -x is the point (-y, -x).

Step-by-step explanation:

Hope you understand

4 0
3 years ago
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