2sec^2x - secx - 1 = 0

1 answer:

8 0

What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0

Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1

I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!

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How can a rational number and irrational number when multiplied together make a irrational number ?

pochemuha

Answer:

"The product of a rational number and an irrational number is SOMETIMES irrational." If you multiply any irrational number by the rational number zero, the result will be zero, which is rational. Any other situation, however, of a rational times an irrational will be irrational

A better statement would be:

"The product of a non-zero rational number and an irrational number is irrational