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V125BC [204]
2 years ago
13

100 points !!! Please help

Mathematics
1 answer:
noname [10]2 years ago
8 0
DERIVATIVE \: \: OF \: \: \\ \: \: \: \: \:PARAMETRIC \: \: FUNCTIONS\\ \\ \\ x = a( \beta - \sin( \beta ) ) \\ y = a(1 - \cos( \beta ) \\ \\ \frac{dy}{d \beta } = a \sin( \beta ) \\ \\ \frac{dx}{d \beta } = a(1 - \cos( \beta ) \\ \\ \frac{dy}{dx} = \frac{a \sin( \beta ) }{a(1 - \cos( \beta ) } = \cot( \frac{ \beta }{2} ) \\ \\ \\ \frac{d^{2}y }{d {x}^{2} } = \frac{d}{dx} ( \ \ \cot ( \frac{ \beta }{2} ) ) = ( - \frac{1}{2} cosec ^{2} \frac{ \beta }{2} ) \times \frac{d \beta }{dx} \\ \\ \\ = (- \frac{1}{2} cosec^{2} \frac{ \beta }{2} ) \times \frac{1}{a(1 - \cos( \beta ) } \\ \\ \\ At \: \beta = \pi \\ \\ = ( - \frac{ 1}{2} {cosec}^{2}\frac{\pi}{2} ) \times \frac{1}{a(1 - \cos(\pi)) } \\ \\ = - \frac{1}{2} . {1}^{2} \times \frac{1}{a(1 - ( - 1))} \\ \\ \\ = - \frac{1}{4a} \: \: \: \: \: \: \: \: \: Ans.
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A jewelry maker has 24 jade beads and 30 teak beads. What the the greatest number of necklaces she can make? How many beads of e
Darya [45]
Find the GCF of 24 and 30

  24                30
1×24              1×30
2×12             2×15
3×8               3×10
4×6               5×6

The common factors are 1, 2, 3, and 6

That means we can make 6 necklaces, each necklace with 4 jade beads and 5 teak beads. 

8 0
3 years ago
Read 2 more answers
I NEED HELP WITH THIS PLEASE!!!!!
kumpel [21]

Answer:

nt ooooo

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Step-by-step explanation:

5 0
2 years ago
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ss7ja [257]
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5 0
3 years ago
Solve each equation for the variable
motikmotik

Answer:

X= -50

Step-by-step explanation:

Remove the parenthesis

multiply both sides by two

x - 6 =  -56

Move the 6 to the other side

x = -56 + 6

x = -50

6 0
3 years ago
I don’t know what this is
svet-max [94.6K]

From the graph given

For f(x), where x = 3, on the graph f(3) is

f(3)=6

For g(x), where x = 3, on the graph g(3) is

g(3)=6

Hence,

f(3)=g(3)

The answer is the second option

3 0
1 year ago
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