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3 years ago

If a polynomial function f(x) has roots –9 and 7 – i, what must be a factor of f(x)?

1 answer:

7 0

F(x) has roots -9, and 7 - i.

Therefore x = -9, x = 7 -i

x + 9 = 0 x - 7 + i = 0

(x + 9) must be a factor. (x + i - 7) must also be a factor.

Therefore (x + 9) and (x + i - 7) must be factors.

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What is the word for a rational number whose cube root is a whole number

xxTIMURxx [149]

It's called perfect cubes

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3 years ago

Hi, can you help me answer this question, please, thank you!

frutty [35]

Given:

mean, u = 0

standard deviation σ = 1

Let's determine the following:

(a) Probability of an outcome that is more than -1.26.

Here, we are to find: P(x > -1.26).

Apply the formula:

$z=\frac{x^{\prime}-u}{\sigma}$

Thus, we have:

$\begin{gathered} P(x>-1.26)=\frac{-1.26-0}{1} \\ \\ P(x>-1.26)=\frac{-1.26}{1}=-1.26 \end{gathered}$

Using the standard normal table, we have:

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(b) Probability of an outcome that

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1 year ago

How much grain can this container hold?

ludmilkaskok [199]

Answer:

953.78 in^3 of grain.

Step-by-step explanation:

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For this cylinder r = radius of the base = 9/2

= 4.5 in and the height h = 15 in

So the volume is 3.14 * 4.5^2 * 15

= 953.78 in^3.

8 0

3 years ago

Read 2 more answers

Which one is it I’m so confused?

Ad libitum [116K]

Answer:

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Step-by-step explanation:

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3 years ago

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What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti

Marat540 [252]

Answer:

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

Step-by-step explanation:

Given

$x^2 - 5x - 7 = 0$

Required

Solve for x using:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

First, we need to identify a, b and c

The general form of a quadratic equation is:

$ax^2 + bx + c = 0$

So, by comparison with $x^2 - 5x - 7 = 0$

$a = 1$ $b = -5$ $c = -7$

Substitute these values of a, b and c in

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}$

$x = \frac{5 \± \sqrt{25 +28}}{2}$

$x = \frac{5 \± \sqrt{53}}{2}$

Split the expression to two

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

To solve further in decimal form, we have

$x = \frac{5 + 7.28}{2}$ or $x = \frac{5 - 7.28}{2}$

$x = \frac{12.28}{2}$ or $x = \frac{-2.28}{2}$

$x = 6.14$ or $x = -1.14$

4 0

3 years ago