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Stolb23 [73]
4 years ago
5

A baseball was hit and reached its maximum height in 3.00s. Find (a) its initial velocity; (b) the height it reaches.[29.4 m/s;

44.1m]
Physics
1 answer:
kicyunya [14]4 years ago
4 0

Answer:

u= 29.43 m/s

h=44.14 m

Explanation:

Given that

t= 3 s

We know that acceleration due to gravity ,g = 9.81 m/s² (Downward)

Initial velocity  = u

Final velocity ,v= 0 (At maximum height)

We know v = u +a t

v=final velocity

u=initial velocity

a=Acceleration

Now by putting the values in the above equation

0 = u - 9.81 x 3

u= 29.43 m/s

The maximum height h is given as

v² = u ² -  2 g h

0² = 29.43 ² - 2 x 9.81 x h

h=\dfrac{29.43^2}{2\times 9.81}\ m

h=44.14 m

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(a) The frequency of water wave is 2 Hz.

(b) The wave speed of the water wave is 3.6 m/s.

<u>Explanation:</u>

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