To determine the maximum height for the projectile, we can use the timeless kinematics equation
and plug in what we know. For
, we know it is zero because at the highest location of flight, there is no vertical velocity. For
, we know it is
since the vertical component is the sine of the velocity. We need to solve for
, so it is left as-is. Since the only acceleration is
, we can substitute -9.81 into it. Solving for the equation yields a solution of 17.55 m for
.
"60 kg" is not a weight. It's a mass, and it's always the same
no matter where the object goes.
The weight of the object is
(mass) x (gravity in the place where the object is) .
On the surface of the Earth,
Weight = (60 kg) x (9.8 m/s²)
= 588 Newtons.
Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to 5R from the center, the gravity out there is
(1R/5R)² = (1/5)² = 1/25 = 0.04 of its value on the surface.
The object's weight would also be 0.04 of its weight on the surface.
(0.04) x (588 Newtons) = 23.52 Newtons.
Again, the object's mass is still 60 kg out there.
___________________________________________
If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink.
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.
Where is the phone ? Can’t answer without a picture of the problem
Answer:
Option B is the correct answer.
Explanation:
Period of simple pendulum is given by the expression 
, where l is the length of pendulum and g is the acceleration due to gravity value.
So if we have a simple pendulum with length l we can find its period. Using the above formula we can calculate acceleration due to gravity value of that place.
So using simple pendulum we can measure acceleration due to gravity value.
Option B is the correct answer.
Answer:
Explanation:
Coding is all about logic, since I do not have the actual problem from the website I will guide you on how to solve this.
Since you need to go a certain direction you will need to indicate to the character which direction to go. Next, we need to prevent the player from travelling through a wall, we can accomplish this using an IF/ELSE statement. IF the next block in that direction is a wall then do not move forward, ELSE move forward. We would call this statement every time the player tries to move in any direction. Finally, once we reach the lettuce we need to continue picking it until there is no more. To do this we use a While loop, that checks to see if there is any more lettuce, if there is it will run the code to pick up lettuce, if there is NO more then the While loop will exit. That would be the entire code.
