Answer:4.5 joules
Explanation:
charge=3c
Potential difference=1.5v
Work=potential difference x charge
Work=1.5 x 3
Work=4.5
Work=4.5 joules
The initial velocity of the sky diver would be t=0. So put that into the equation:
<span>v(0)=64(1−<span>e<span>(−0.19)(0)</span></span>)
and for b it will be
</span><span>(5)=64(1−<span>e<span>(−0.19)(5)</span></span>)</span><span>, and likewise for t=15. You just need to throw it in a calculator.</span>
Answer:
a) p₀ = 1.2 kg m / s, b) p_f = 1.2 kg m / s, c) θ = 12.36, d) v_{2f} = 1.278 m/s
Explanation:
For this exercise we define a system formed by the two balls, which are isolated and the forces during the collision are internal, therefore the moment is conserved
a) the initial impulse is
p₀ = m v₁₀ + 0
p₀ = 0.6 2
p₀ = 1.2 kg m / s
b) as the system is isolated, the moment is conserved so
p_f = 1.2 kg m / s
we define a reference system where the x-axis coincides with the initial movement of the cue ball
we write the final moment for each axis
X axis
p₀ₓ = 1.2 kg m / s
p_{fx} = m v1f cos 20 + m v2f cos θ
p₀ = p_f
1.2 = 0.6 (-0.8) cos 20+ 0.6 v_{2f} cos θ
1.2482 = v_{2f} cos θ
Y axis
p_{oy} = 0
p_{fy} = m v_{1f} sin 20 + m v_{2f} cos θ
0 = 0.6 (-0.8) sin 20 + 0.6 v_{2f} sin θ
0.2736 = v_{2f} sin θ
we write our system of equations
0.2736 = v_{2f} sin θ
1.2482 = v_{2f} cos θ
divide to solve
0.219 = tan θ
θ = tan⁻¹ 0.21919
θ = 12.36
let's look for speed
0.2736 = v_{2f} sin θ
v_{2f} = 0.2736 / sin 12.36
v_{2f} = 1.278 m / s
Answer:
The object will have an upward acceleration
Explanation:
Let's consider the forces applied on the box. We have only two forces:
- The applied force of push,
, downward
- The force of gravity,
, (also known as weight of the object), downward
Therefore, the net force on the box is:

Here, we know that force applied is equal or greater than the weight, so

And therefore the net force is greater than zero:
(1)
According to Newton's second law of motion, the net force on the box is equal to the product between its mass and its acceleration:

where
m is the mass of the box
a is its acceleration
Given (1), this means that

Therefore, the box will have an upward acceleration.
In this case force example we have:

So the mass of the box is

So the net force is

And the acceleration is

False. Mass doesn't depend on location or gravity. It doesn't change.