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kkurt [141]
3 years ago
6

Which of the examples below represents velocity correctly

Physics
2 answers:
yan [13]3 years ago
8 0

Answer:

D

Explanation:

The reason why it's D is because it show a real life example were you can use velocity

arlik [135]3 years ago
3 0

Answer:

the answer is B

Explanation:

I do online school and it said the answer was B.

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How much work is done to move 3c of charge through a potential difference of 1.5v
kaheart [24]

Answer:4.5 joules

Explanation:

charge=3c

Potential difference=1.5v

Work=potential difference x charge

Work=1.5 x 3

Work=4.5

Work=4.5 joules

4 0
3 years ago
A sky diver jumps from a reasonable height above the ground. The air resistance she experiences is proportional to her velocity,
ch4aika [34]

The initial velocity of the sky diver would be t=0. So put that into the equation:

<span>v(0)=64(1−<span>e<span>(−0.19)(0)</span></span>)

and for b it will be
</span><span>(5)=64(1−<span>e<span>(−0.19)(5)</span></span>)</span><span>, and likewise for t=15. You just need to throw it in a calculator.</span>

7 0
3 years ago
In a game of pool, the cue ball moves at a speed of 2 m/s toward the eight ball. When the cue ball hits the eight ball, the cue
Andru [333]

Answer:

a)  p₀ = 1.2 kg m / s,  b) p_f = 1.2 kg m / s,  c)   θ = 12.36, d)  v_{2f} = 1.278 m/s

Explanation:

For this exercise we define a system formed by the two balls, which are isolated and the forces during the collision are internal, therefore the moment is conserved

 

a) the initial impulse is

         p₀ = m v₁₀ + 0

         p₀ = 0.6 2

         p₀ = 1.2 kg m / s

b) as the system is isolated, the moment is conserved so

        p_f = 1.2 kg m / s

we define a reference system where the x-axis coincides with the initial movement of the cue ball

 

we write the final moment for each axis

X axis

         p₀ₓ = 1.2 kg m / s

         p_{fx} = m v1f cos 20 + m v2f cos θ

         p₀ = p_f

        1.2 = 0.6 (-0.8) cos 20+ 0.6 v_{2f} cos θ

         1.2482 = v_{2f} cos θ

Y axis  

        p_{oy} = 0

        p_{fy} = m v_{1f} sin 20 + m v_{2f} cos θ

        0 = 0.6 (-0.8) sin 20 + 0.6 v_{2f} sin θ

        0.2736 = v_{2f} sin θ

we write our system of equations

         0.2736 = v_{2f} sin θ

         1.2482 = v_{2f} cos θ

divide to solve

         0.219 = tan θ

          θ = tan⁻¹ 0.21919

          θ = 12.36

let's look for speed

            0.2736 = v_{2f} sin θ

             v_{2f} = 0.2736 / sin 12.36

            v_{2f} = 1.278 m / s

4 0
3 years ago
**
lys-0071 [83]

Answer:

The object will have an upward acceleration

Explanation:

Let's consider the forces applied on the box. We have only two forces:

- The applied force of push, F_p, downward

- The force of gravity, W, (also known as weight of the object), downward

Therefore, the net force on the box is:

F_{net}=F_p -W

Here, we know that force applied is equal or greater than the weight, so

F_p \geq W

And therefore the net force is greater than zero:

F_{net}\geq 0 (1)

According to Newton's second law of motion, the net force on the box is equal to the product between its mass and its acceleration:

F_{net}=ma

where

m is the mass of the box

a is its acceleration

Given (1), this means that

a\geq 0

Therefore, the box will have an upward acceleration.

In this case force example we have:

F_p = 100 N\\W = 40 N

So the mass of the box is

m=\frac{W}{g}=\frac{40}{10}=4 kg

So the net force is

F_{net}=F_p-W=100-40=60 N

And the acceleration is

a=\frac{F_{net}}{m}=\frac{60}{4}=15 m/s^2

4 0
3 years ago
Ali has less mass flying in a jet high above the earth than when she stands on the surface of the earth. True False
andrey2020 [161]
False. Mass doesn't depend on location or gravity. It doesn't change.
3 0
3 years ago
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