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nekit [7.7K]
3 years ago
9

Is the following equation balanced? Mg + 2HCl MgCl2 + H2 yes no

Chemistry
2 answers:
Rzqust [24]3 years ago
7 0

yes


is


the


answer


hope


it


helps


:^)

viva [34]3 years ago
4 0
<h3>Answer </h3>

Yes

<h3>Explanation </h3>

Magnesium reacts with hydrochloric acid according to the equation:  

Mg(s) + 2 HCl(aq) --> MgCl2(aq) + H2(g)  

This demonstration can be used to illustrate the characteristic reaction of metals with acid, a single replacement reaction, or to demonstrate the generation of hydrogen gas.

When magnesium reacts with hydrochloric acid, hydrogen gas and soluble magnesium chloride are produced. It takes place because magnesium is more reactive than hydrogen so it displaces it in the chloride compound. Magnesium is oxidized losing two electrons. Hydrogen is reduced from H+ ion to H2 gas when electron from magnesium is transferred to it.


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Answer:

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3 years ago
Pls help me !!!! Is for chemistry
Sphinxa [80]

Answer:

Explanation:

1) Molarity of the solution is (0.50/0.75)x1 = 0.66666 Mol/L

2) Molar mass of NaCl is 23+35 = 58g

Molarity = (0.5/58)/0.075 = 0.115 Mol/L

3) Molar mass of Li_{2}SO_{4} = 7x2 + 32 + 16x2 = 78g

Molarity = (734/78)/0.875 = 10.754 Mol/L

5) Molar mass of   Pb(C_{2}H_{3}O_{2})_{4}

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Molarity = (0.0672/443.2)/0.1335 = 0.001135 Mol/L

6) Both are the same.

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Solution 2 Molarity = 1.0/1.0 = 1 Mol/L

Molarities of the solutions are the same.

7 0
3 years ago
The resulting daughter isotope that is formed when the atom astatine-213 undergoes alpha emission is: ​
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3 years ago
0.22 L of HNO3 is titrated to equivalence using 0.10 L of 0.1 MNaOH. What is the concentration of the HNO3?
White raven [17]

Answer:- Molarity of the acid solution is 0.045M.

Solution:- The balanced equation for the reaction of given acid and base is:

HNO_3+NaOH\rightarrow NaNO_3+H_2O

From the balanced equation, they react in 1:1 mol ratio. So, we could easily solve the problem using the equation:

M_aV_a=M_bV_b

where, M_a is the molarity of acid, M_b is the molarity of base, V_a is the volume of acid and V_b is the volume of base.

Let's plug in the given values in the equation:

M_a(0.22L)=0.1M(0.10L)

on rearranging the above equation:

M_a=\frac{0.1M(0.10L)}{0.22L}

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3 0
3 years ago
When a diprotic acid is titrated with a strong base, and the Ka1 and Ka2 are significantly different, then the pH vs. volume plo
dezoksy [38]

Complete question is;

When a diprotic acid is titrated with a strong base, and the Ka1 and Ka2 are significantly different, then the pH vs. volume plot of the titration will have

a. a pH of 7 at the equivalence point.

b. two equivalence points below 7.

c. no equivalence point.

d. one equivalence point.

e. two distinct equivalence points

Answer:

Option E - Two Distinct Equivalence points

Explanation:

I've attached a sample diprotic acid titration curve.

In diprotic acids, the titration curves assists us to calculate the Ka1 and Ka2 of the acid. Thus, the pH at the half - first equivalence point in the titration will be equal to the pKa1 of the acid while the pH at the half - second equivalence point in a titration is equal to the pKa2 of the acid.

Thus, it is clear that there are two distinct equivalence points.

4 0
4 years ago
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