When aluminum metal is made to contact with chlorine gas (Cl₂), a highly exothermic reaction proceeds. This produces aluminum chloride (AlCl₃) powder. The balanced chemical equation for this reaction is shown below:
2Al(s) + 3Cl₂(g) → 2AlCl₃(s)
Since it was stated that aluminum is in excess, this means that the amount of AlCl₃ produced will only depend on the amount of Cl₂ gas available. The molar mass of Cl₂ is 70.906 g/mol. Using stoichiometry, we have the following equation:
(21.0 g Cl₂/ 70.906 g/mol Cl₂) x 2 mol AlCl₃/ 2 mol Cl₂ = 0.1974 mol AlCl₃
Thus, we have determined that 0.1974 <span>moles of aluminum chloride can be produced from 21.0 g of chlorine gas. </span>
<span>The number of electrons in an atom's outermost valence shell governs its bonding behavior.
In N</span>₂, three electrons are being shared by each nitrogen atom, making a total of 6 shared electrons.
In CCl₄, 4 electrons are being shared by each carbon atom and 1 electron is being shared by each chlorine atom
In SiO₂, 4 electrons are being shared by each silicon atom and 2 electrons are being shared by each oxygen atom.
In AlCl₃, 3 electrons are being shared by each aluminum atom and 1 electron is being shared by each Cl atom
In CaCl₂, 2 electrons are lost by the calcium atom and 1 electron is gained by each chlorine atom
In LiBr, 1 electron is lost by the lithium atom and 1 electron is gained by the bromine atom
Answer:
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Answer:
Lewis structure in attachment.
Explanation:
Atoms of elements in and beyond the third period of the periodic table form some compounds in which more than eight electrons surround the central atom. In addition to the 3s and 3p orbitals, elements in the third period also have 3d orbitals that can be used in bonding. These orbitals enable an atom to form an <u>expanded octet</u>.
The central Xe atom in the XeF₄ molecule has <u>two</u> unbonded electron pairs and <u>four</u> bonded electron pairs in its valence shell.
Answer:
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Explanation: Thats your answer
