Let us say the number was x.
Mike added to it two other numbers.
First number added is 12 less than the original number.
So first number is x-12.
Second number added is 12 more than the original number.
So second number is x+12.
Now we are given that the result of adding all three numbers is 15.
Converting the information given into equation, we have:
original number + first number + second number =15
Adding like terms,
dividing both sides by 3,
x=5
Answer: So the original number that Mike thought was 5.
Answer:
x^2+11x+30
Step-by-step explanation:
(x+6)(x+5)
x^2+5x+6x+30
x^2+11x+30
The way that I would explain it is that you have 3610 and it is a whole number there basically 3 numbers so the 3 would be in the ones place 6 in the tenth and 1 in the hundredths place and your answer is 3.61 or another is .361
Since:
ax(2x + y - 5) = 6x^2 +3xy - 15x,
we should factor X out of the second equation to find out the value of a:
6x^2 + 3xy - 15x =
x(6x + 3y - 15),
Now that we factored X out, to find a, we need to find the other common factor:
(6x + 3y - 15) / (2x + y - 5),
which is 3.
Hence the value of a is 3
Answer: 14 students will be in each group
84 divided by 6 = 14
