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3 years ago

Elaine scored 19 out of 24 on her science test.

Mathematics

2 answers:

Fudgin [204]3 years ago

7 0

Answer:

Addison did better on the test. I know because I converted Elaine's mark to a percentage so that I could compare them.

Step-by-step explanation:

Hey there!

Elaine is $\frac{19}{24}$ = 79.16%

Addison is 81.25

~I hope I helped you! :)~

kozerog [31]3 years ago

4 0

Answer:

Addison scored a better score on the test.

Step-by-step explanation:

Elaine's score can be found by dividing 19 by 24, which yields a result of 0.7916, which means her score is a 79 out of 100 (79%). Her score can also be found by doing 100/24 = 4.16666 repeating and multiplying that by 19, which also yields 79.6. Hope this helps!

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Will switching points when calculating distance affect the final answer? Explain.

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Answer:

I think it's B or C but I'm not sure cuz I'm struggling with this question also

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3 years ago

The first term of a geometric sequence is 15, and the 5th term of the sequence is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B24

sladkih [1.3K]

The geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

Explanation:

Given that the first term of the geometric sequence is 15

The fifth term of the sequence is $\frac{243}{125}$

We need to find the 2nd, 3rd and 4th term of the geometric sequence.

To find these terms, we need to know the common difference.

The common difference can be determined using the formula,

$a_n=a_1(r)^{n-1}$

where $a_1=15$ and $a_5=\frac{243}{125}$

For $n=5$ , we have,

$\frac{243}{125}=15(r)^4$

Simplifying, we have,

$r=\frac{3}{5}$

Thus, the common difference is $r=\frac{3}{5}$

Now, we shall find the 2nd, 3rd and 4th terms by substituting $n=2,3,4$ in the formula $a_n=a_1(r)^{n-1}$

For $n=2$

$a_2=15(\frac{3}{5} )^{1}$

$=9$

Thus, the 2nd term of the sequence is 9

For $n=3$ , we have,

$a_3=15(\frac{3}{5} )^{2}$

$=15(\frac{9}{25} )$

$=\frac{27}{5}$

Thus, the 3rd term of the sequence is $\frac{27}{5}$

For $n=4$ , we have,

$a_4=15(\frac{3}{5} )^{3}$

$=15(\frac{27}{25} )$

$=\frac{81}{25}$

Thus, the 4th term of the sequence is $\frac{81}{25}$

Therefore, the geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

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3 years ago

A group of hikers walks 3 miles east and then 1 mile north. After taking a break, they then hike 4 miles east to their final des

geniusboy [140]

Answer:

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Step-by-step explanation:

In this problem we assume that orthogonal axes coincide with the north and east. We proceed to translate each sentence from statement into vectorial equations:

(i) A group of hikers walks 3 miles east and then 1 mile north:

$\vec r_{A} = 3\,\hat{i}+1\,\hat{j}\,\,\,[mi]$