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Arte-miy333 [17]
3 years ago
8

Express the area of the triangle shown below in terms of b and θ only.

Mathematics
1 answer:
Paul [167]3 years ago
8 0
Given a right triangle with base, b and height, h with the angle opposide side h as θ.

The area of a triangle is given by
A= \frac{1}{2} bh

But,
\tan\theta= \frac{h}{b}  \\  \\ \Rightarrow h=b\tan\theta

Therefore, the area of the triangle in terms of <span>b and θ only is given by
A= \frac{1}{2} b(b\tan\theta)= \frac{1}{2} b^2\tan\theta</span>
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A number increased by the quotient of 24 and the number
ValentinkaMS [17]

Answer:

n + 24/n

Step-by-step explanation:

n = number

24/n = quotient

Expression: n + 24/n

8 0
3 years ago
The midpoint of AB is M(1,-2). If the coordinates of A are (-3, -8), what are
shtirl [24]

Answer:

Step-by-step explanation:

(x - 3)/2= 1

x - 3 = 2

x = 5

(y - 8)/2 = -2

y - 8 = -4

y = 4

(5, 4) coordinates for B

3 0
3 years ago
1. Mr. Davis deposited $1,250 into an account. He made no additional deposits or
cluponka [151]

Answer:mn jjjjjjjjjjjjjjjjjjjjjjjj,uyhhhbgfvStep-by-step explanation:

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6 0
2 years ago
The foot of a ladder is placed 10 feet from a wall. If the top of the ladder rests 13 feet up on the wall, find the length of th
Minchanka [31]
10 squared + 13 squared = your answer squared.
So do that then take the square root of whatever you get.
4 0
3 years ago
Describe and correct the error in finding csc θ, given that θ is an acute angle of a right triangle and cos θ =7/11
a_sh-v [17]

Answer:

<h2>cosecθ = 1/sinθ = 11/6√2</h2>

Step-by-step explanation:

Given that  cos θ =7/11, cosec θ = 1/sinθ in trigonometry.

Based on SOH, CAH, TOA;

cosθ = adjacent/hypotenuse = 7/11

adjacent = 7 and hyp = 11

Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.

Using pythagoras theorem to get the opposite;

hyp^{2} = adj^{2}  + opp ^{2}  \\opp = \sqrt{hyp^{2} - adj^{2}  } \\opp = \sqrt{11^{2} - 7^{2}} \\opp = \sqrt{72} \\opp = 6\sqrt{2}

sinθ = 6√2/11

cosecθ = 1/sinθ = 1/( 6√2/11)

cosecθ = 1/sinθ = 11/6√2

Note the error; cscθ\neq 1/cosθ but cscθ = 1/sinθ

6 0
3 years ago
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