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Arte-miy333 [17]
3 years ago
8

Express the area of the triangle shown below in terms of b and θ only.

Mathematics
1 answer:
Paul [167]3 years ago
8 0
Given a right triangle with base, b and height, h with the angle opposide side h as θ.

The area of a triangle is given by
A= \frac{1}{2} bh

But,
\tan\theta= \frac{h}{b}  \\  \\ \Rightarrow h=b\tan\theta

Therefore, the area of the triangle in terms of <span>b and θ only is given by
A= \frac{1}{2} b(b\tan\theta)= \frac{1}{2} b^2\tan\theta</span>
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ExtremeBDS [4]

Answer:

the question is about the table you have to make a table it is very easy

6 0
2 years ago
, list the first five terms of each sequence, and identify them as arithmetic or geometric.
Serhud [2]

Answer:

The first 5 terms are -6,-25,-44,-63 and -82

The sequence is arithmetic

Step-by-step explanation:

Given that A(n + 1) = A(n) − 19 for n ≥ 1 and A(1) = −6

A(1) = -6

A(2) = A(1) − 19 = -6 - 19 = -25

A(3) = A(2) − 19 = -25 - 19 = -44

A(4) = A(3) − 19 = -44 - 19 = -63

A(5) = A(4) − 19 = -63 - 19 = -82

So the first 5 terms are -6,-25,-44,-63 and -82

If they are in arithmetic the common difference will be same, if geometric common ratio will be same.

Let us check common difference,

                       -25-(-6) = -19

                       -44-(-25) = -19

                       -63-(-44) = -19

                       -82-(-63) = -19

So common difference is same, so the sequence is arithmetic.

3 0
3 years ago
I really need help with this, I'll give Brainliest to whoever answers correctly!
alexgriva [62]

Answer:

B) 5 5/8in x 9in is your answer

Step-by-step explanation:

First add the bottom numbers together (9+6+9) which gives you 24. Then multiply both sides by 3/8 (15 x 3/8= 5 <u>5/8</u>) and (24 x 3/8= <u>9</u>) making your answer 5 5/8 x 9

5 0
3 years ago
A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ
ElenaW [278]

Answer:

n(S\cap F \cap R)=7

Step-by-step explanation:

The Universal Set, n(U)=2092

n(S)=1232\\n(F)=879\\n(R)=114

n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14

Let the number who take all three subjects, n(S\cap F \cap R)=x

Note that in the Venn Diagram, we have subtracted n(S\cap F \cap R)=x from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, n(S\cap F \cap R)=7

3 0
3 years ago
1/2+1/3 plsssssssss awnser
iogann1982 [59]

Answer:

5/6

or

0.833...

Step-by-step explanation:

Hope this helps!

3 0
3 years ago
Read 2 more answers
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