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prisoha [69]
3 years ago
9

I need help solving this

Mathematics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

slope =m = -1/5

c = -6

y = mx+c

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P² +6r - 27<br> factoring quadratics
babunello [35]

Step-by-step explanation:

look at the picture shown

5 0
3 years ago
Help? I'd Appreciate it!
kondor19780726 [428]

<u>Answer</u>

y = (1/2)x - 1


<u>Explanation</u>

The first step is to get the gradient of the line.

The two points in the line are; (2,0) and (-2, -2).

Gradient = (-2 - 0)/(-2, - 2)

                = -2/-4

                 = 1/2

To get the function we use one of the point (2,0) and a general point (x,y).

1/2 = (y - 0)/(x - 2)

1/2 = y/(x - 2)

(x - 2) = 2y

2y = x - 2

y = (1/2)x - 1

8 0
3 years ago
Let f(x) = log(x). Find values of a such that f(kaa) = kf(a).
meriva

Answer:

a = k^{\frac{1}{k-2}}

Step-by-step explanation:

Given:

f(x) = log(x)

and,

f(kaa) = kf(a)

now applying the given function, we get

⇒ log(kaa) = k × log(a)

or

⇒ log(ka²) = k × log(a)

Now, we know the property of the log function that

log(AB) = log(A) + log(B)

and,

log(Aᵇ) = b × log(A)

Thus,

⇒ log(k) + log(a²) = k × log(a)         (using log(AB) = log(A) + log(B) )

or

⇒ log(k) + 2log(a) = k × log(a)            (using log(Aᵇ) = b × log(A) )

or

⇒ k × log(a) - 2log(a) = log(k)

or

⇒ log(a) × (k - 2) = log(k)

or

⇒ log(a) = (k - 2)⁻¹ × log(k)

or

⇒ log(a) = \log(k^{\frac{1}{k-2}})          (using log(Aᵇ) = b × log(A) )

taking anti-log both sides

⇒ a = k^{\frac{1}{k-2}}

3 0
3 years ago
Combine the like terms to create an equivalent expression <br> 4z- (-3z)
NNADVOKAT [17]

Answer:

7z

Step-by-step explanation:

subtracting a negative is like adding

4z - (-3z)\\4z+3z\\7z

4 0
3 years ago
ASAP!!! Which side of the original parallelogram corresponds to the y-centimeter side of the enlarged parallelogram? Explain how
alina1380 [7]

Answer is D

I took the test

5 0
3 years ago
Read 2 more answers
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