Notice in the first transformation, the y values don't change while the x becomes the opposite, that means the points are reflected across the y axis.
in the second transformation, notice that the x values don't change, the y values are decreased by 6, so all the points are moved straight downward 6 units.
To start with, the pentagon is in the second quadrant. You can tell because all the x values are negative and all the y values are positive. Reflected across the y axis, the image is in the first quadrant. shifted down 6 units, all the vertex are in the fourth quadrant.
If we are to use a single transformation to put the original image in the 4th quadrant, the only choice is b). b) puts the pentagon in the 1st, then in the 4th quadrant.
a) puts it in the 3rd quadrant, c) makes the image go back to where it was d)puts the image in the 1st quadrant.
I tried to answer this question before but I thought the two methods needed to produce two overwrapping images, that is, I thought they needed to end up at exact the same spot. I couldn't figure out how. If the two images just need to be in the same quadrant, my answer is b.
I hope my explanation makes sense. And I hope I am right.
This is a tough one for middle school.
1. 8
2. 9
3. 11
4. 8
5. 10
6. 7
7. 4
8. 11
9. 4
10. 10
11. 16
12. 10
13. 22
14. 3
15. 16
Answer:
(16 + 8√3) in²
Step-by-step explanation:
The ratio of side dimensions for a 30°-60°-90° triangle are 1 : √3 : 2. If we call the horizontal dimension of the triangle its base, then its height (vertical dimension) will be √3×4 in. Of course the area of the triangle is ...
... A = (1/2)bh = (1/2)(4 in)(4√3 in) = 8√3 in²
The total sod area is the sum of the square area (16 in²) and the triangle area, so is ...
... area to cover = (16 +8√3) in²
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<em>Comment on problem dimensions</em>
The area involved here is not much larger than the size of your hand. It would make more sense for the dimensions to be in feet or yards or meters, rather than inches.
Answer:
23 yards
Step-by-step explanation:
During a test flight, Jeri's rocket reached a height of 18 yards. This was 7 yards less than the height of Devon's rocket. Write and solve a subtraction equation to find the height of Devon's rocket.
Let us represent the height of Devon's rocket = x
18 yards = x - 7 yards
x = 18 yards + 7 yards
x = 23 yards
The height of Devon's rocket = 23 yards