4 years ago

the perimeter of a photo frame is 36 inches. The length is 2 inches greater than the width. what are the dimensions of the frame

Mathematics

1 answer:

Tamiku [17]4 years ago

5 0

Length = 10
Width = 8

Hope this helped! A lot of thinking went into this one!

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3 years ago

Mr. Jones replace 40% of the lights on a Christmas tree. If he replaced 30 lights, how many lights are on the tree total?

oksian1 [2.3K]

Since 30 lights are 40% of them:

30*2= 60

Since 2*40= 80

We still need the 20 percent.

Half of 40= 20.

30/2= 15

So, 15+60= 75

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4 years ago

Read 2 more answers

PLZPLZPLZ HELP ME!!!

zhannawk [14.2K]

If $\ell$ is the length and $w$ the width, then $\ell=2w-2$ .

Since the area of the rectangle is

$\ell w=40$

you have

$(2w-2)w=40\implies 2w^2-2w-40=0\implies w^2-w-20=0$

Factoring the left hand side gives

$(w-5)(w+4)=0\implies w=5,w=-4$

Obviously the width can't be negative, so $w=5$ . This means D is the answer, since it's the only option with this measure.