Question

PLZPLZPLZ HELP ME!!!

Answer 1

If $\ell$ is the length and $w$ the width, then $\ell=2w-2$.

Since the area of the rectangle is

$\ell w=40$

you have

$(2w-2)w=40\implies 2w^2-2w-40=0\implies w^2-w-20=0$

Factoring the left hand side gives

$(w-5)(w+4)=0\implies w=5,w=-4$

Obviously the width can't be negative, so $w=5$. This means D is the answer, since it's the only option with this measure.