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2 years ago

PLEASE HURRY AND SOLVE. THIS IS FOR A QUIZ THAT I CANNOT RETAKE I WILL MARK BRAINLIEST TO WHOEVERS SOLVES THIS CORRECTLY FIRST

Mathematics

1 answer:

GalinKa [24]2 years ago

3 0

Answer:

B>-42

Step-by-step explanation:

Multiply 6 on both sides

youll get B

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Jillian needs to buy a new laptop for the school year. The list price for the laptop is $479.99. Is it a better

Galina-37 [17]

Answer:

$100 rebate

Step-by-step explanation:

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3 years ago

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I need to divide and then write in simplest form 2/5÷1/6

My name is Ann [436]

Answer:

2/5÷1/6 = 2/1

Step-by-step explanation:

2/5÷1/6 = 2/5 times 6/1 = 12/5, 12÷2 is 6, 5 ÷ 5 is 1, so it's 2/1.

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2 years ago

What is the equation of a line that has a slope of 0 and a y-intercept of 4

finlep [7]

Answer:

y = 4

since you cant have y = 0x + 4, you drop the x and have a straight line (slope of 0) that runs all along the y point of 4.

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3 years ago

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Find sec A and cot B exactly if a = 8 and b = 7.

Shtirlitz [24]

Answer:

sec A= 1.01 and cot B =8.25

Step-by-step explanation:

Given :

sec A and cotB if a =8 and b=7

Now,

= $sec A=\frac{1}{cos A} \\\\\frac{1}{cos 8} \\\\\frac{1}{0.99} \\1.01$

and

$cot B=\frac{cosB}{sin B} \\cotB=\frac{cos 7}{sin7} \\cot B =\frac{0.99}{0.12} \\cot B =8.25$

Therefore, answer will be sec A= 1.01 and cot B =8.25

8 0

2 years ago

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

2 years ago