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2 years ago

Write the column B the reverse pertuna

Mathematics

1 answer:

sweet-ann [11.9K]2 years ago

8 0

Answer:

it is 2

Step-by-step explanation:

i think it is

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What is the Internal Revenue Code?

mr_godi [17]

Answer: It’s Title 26 of the U.S. Code that contains nearly all of the federal tax laws.

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3 years ago

Write a recursive rule for the sequence. The sequence may be arithmetic, geometric or neither: 66,33,16.5,8.25,...

nlexa [21]

An=a(n-1)x1/2 A1=66

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3 years ago

Can someone show me how to write the standard form of the line that contains a slope of 2/3 and passes through the point (1, 1)?

8090 [49]

Answer:

$\large\boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}\qquad\text{slope-intercept form}}\\\\\boxed{y-1=\dfrac{2}{3}x-\dfrac{2}{3}\qquad\text{point-slope form}}\\\\\boxed{2x-3y=-1\qquad\text{standard form}}$

Step-by-step explanation:

$\text{The standard form:}\ Ax+By=C$

$\text{The point-slope form:}\\\\y-y_1=m(x-x_1)\\\\m-slope\\\\\text{We have the slope}\ m=\dfrac{2}{3}\ \text{and the point}\ (1,\ 1).\ \text{Substitute:}\\\\\underline{y-1=\dfrac{2}{3}(x-1)}\qquad\text{use the distributive property}\\\\y-1=\dfrac{2}{3}x-\dfrac{2}{3}\qquad\text{add 1 to both sides}\\\\\underline{y=\dfrac{2}{3}x+\dfrac{1}{3}}$

$y=\dfrac{2}{3}x+\dfrac{1}{3}\qquad\text{multiply both sides by 3}\\\\3y=2x+1\qquad\text{subtract 2x from both sides}\\\\-2x+3y=1\qquad\text{change the signs}\\\\\underline{2x-3y=-1}$

3 0

3 years ago

!!PLEASE HELP!! Stuck on this and need some help. !!40PTS!!

sladkih [1.3K]

Answer:

Step-by-step explanation:

c) 2(50%)=75%

d) 1=0.75

e) 1=0.75

4 0

3 years ago

Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

Bond [772]

Taylor series is $f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

$f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }$

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

$f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }$

Following the pattern, we can see that for $f^{n}(x)$ ,

$f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} } \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}$

This applies for n ≥ 1, Expressing f(x) in summation, we have

$\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}$

Combining ln2 with the rest of series, we have

$f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

Taylor series is $f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

Find out more information about taylor series here

brainly.com/question/13057266

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3 0

2 years ago