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3 years ago

14

Please help asap !!!!!!

1 answer:

alukav5142 [94]3 years ago

4 0

Answer:

A.

Step-by-step explanation:

$\sqrt{10} *\sqrt{8}\\ \sqrt{10}*\sqrt{2*4}\\\sqrt{10}*2\sqrt{2}\\2\sqrt{2*10}\\2\sqrt{20}\\ 2\sqrt{4*5} \\4\sqrt{5}$

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Now, suppose one of the roots of the polynomial function is irrational. The roots of the function are 2, <img src="https://tex.z

nikklg [1K]

Irrational roots occurs with its conjugate.

Therefore, -√3 is also root of the function.

The answer is -√3.

6 0

3 years ago

Read 2 more answers

Please answer this will reward brainlest

bixtya [17]

Well 32 x 405 is 12,960, but it ask for 2 numbers added to make 12,960 so the answer is 810 + 12,150 which is 2 products that add up to the answer 12,960.

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3 years ago

Find the value of x.

dimaraw [331]

Answer:

$2\sqrt{77}$

Step-by-step explanation:

Use the Pythagorean theorem. $a^{2} +b^{2}=c^{2}$

a and b are the two side lengths

c is the hypotenuse (value across from the right angle)

Plug in the values that you are given.

$a^{2} +4^{2} =18^{2}$

Solve for x

$x^{2} =18^{2} -4^{2}$

$x^{2} =308$

x= $\sqrt{308}$

$x=2\sqrt{77}$

5 0

3 years ago

A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin

riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

$p=\frac{x}{n}$

$p=\frac{80}{100}$

$p=0.8$

Now we define hypothesis,

Null hypothesis $H_0$ : candidate A is significantly greater than 75%.

Alternative hypothesis $H_1$ : candidate A is not significantly greater than 75%.

Level of significance $\alpha=0.05$

Applying test statistic Z -proportion,

$Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$

Where, $\widehat{p}=80\%=0.80$ and $p=75%=0.75$

Substitute the values,

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}$

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}$

$Z=\frac{0.05}{0.0433}$

$Z=1.1547$

The p-value is

$P(Z>1.1547)=1-P(Z$

$P(Z>1.1547)=1-0.8789$

$P(Z>1.1547)=0.1241$

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

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3 years ago

Based on a poll, 63% of Internet users are more careful about personal information when using a public Wi-Fi hotspot. What is

VashaNatasha [74]

Answer:

So it's a big probability it's a 6 in 4 chance though. 6 is for users that are careful and 4 for users that aren't that careful.

Step-by-step explanation:

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2 years ago