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Pani-rosa [81]
3 years ago
13

HELPPPP. EXPLAIN IT IN 2 SENTENCES

Mathematics
2 answers:
schepotkina [342]3 years ago
6 0
B for 8 would be 6.2 
b for 9 would be 7
The b is adding 0.8 each time
Hope this helps!
alexdok [17]3 years ago
6 0
The pattern is that the b keeps increasing by .8 as the a increases by a. To finish the graph 8a is 6.2 and 9a is 7.
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blagie [28]

Answer:

4

Step-by-step explanation:

all you have to do is divide 12 by 3

3 0
3 years ago
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For what value of c does the following system have no solution?<br><br> 1/2x+1/5y=2<br> 5x+2y=c
Minchanka [31]

Answer:

Step-by-step explanation:

\frac{1}{2}x+\frac{1}{5}y = 2 \mid 5x + 2y = c

First let's multiply the 1st equation by 10.

5x + 2y = 20 \mid 5x + 2y = c

So, we can see that the equations have the same coefficients and that implies  they are equal.

So the equation has no solutions for. c \in R \setminus{20}

3 0
3 years ago
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How do you find the slope using this table? I graphed it too but I can't understand it!
sammy [17]
M=Y2-Y1/X2-X1
M= 1250-1625/4-2.5
M=841.25
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5 0
3 years ago
John invests $3,000 into an account that earns 4.7% interest compounded quarterly. Write an equation and us it to find the value
kow [346]

Answer:

The equation is;

A = 9,000(1 + 0.047/4)^48

The value is

$15,767.28

Step-by-step explanation:

Here we want to find the value of an investment after 12 years, given its interest rate;

Mathematically the amount which is the value would be;

A = I( 1 + r/n)^nt

Where A is the amount in 12 years

I is the initial amount invested = $3,000

r is the interest rate = 4.7% = 4.7/100 = 0.047

n is the number of times interest is compounded yearly = 4 since it is quarterly ( once every three months)

t is the number of years = 12

Substituting these values, we have

A = 9,000(1 + 0.047/4)^(12^4)

A = 9,000(1 + 0.047/4)^48

The above is the expression

A = 9,000(1 + 0.01175)^48

A = 9,000(1.01175)^48

A = $15,767.28

8 0
3 years ago
Solve for x.........................
marin [14]
Sorry I don’t know how to type it

7 0
3 years ago
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