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Komok [63]
3 years ago
7

How do i solve thus equation 7+5(x-2)=12

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0

Answer:

x = 3

Step-by-step explanation:

The goal of solving this equation is finding the value of the variable, "x". To do that, we need to get x alone on one side of the equation.

Our first step is to Combine Like Terms.

(7+5)(x-2)=12\\\\12(x-2)=12

Next, Divide 12 from both sides of the equation.

12(x-2)=12\\\\\frac{12(x-2)}{12}=\frac{12}{12}\\\\x-2=1

Finally, Add 2 to both sides of the equation.

x-2=1\\\\x-2+(2)=1+(2)\\\\x=3

So, x is equal to 3.

ycow [4]3 years ago
3 0

Answer: x=3

Step-by-step explanation:

7+5(x-2)=12

Open bracket

7+5x-10=12

Collect like terms

5x-3=12

5x=12+3

5x=15

X=15/5

X=3

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6\frac{1}{2} = A

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The first step is to use the Distance Formula to figure out the lengths of the two legs:

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* So, by my calculations, we have an isosceles <em>right triangle</em>, and according to the <em>45°-45°-90° triangle theorem</em>, we automatically know that the hypotenuse, <em>RQ</em>, is \sqrt{26}:

30°-60°-90° triangle theorem

2x, x, x√3

↑ ↑ ↑

h leg leg

y

p

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t

e

n

u

s

e

45°-45°-90° triangle theorem

x√2, x, x

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h legs

y

p

o

t

e

n

u

s

e

So now, we have to find the area of the triangle by taking half of either height or base, then multiplying that by the height or base, but since this is an isosceles <em>right</em><em> </em><em>triangle</em><em>,</em><em> </em>it does not matter:

[\frac{h}{2}][b] = A \: \:OR\: \: [\frac{b}{2}][h] = A \: \:OR \: \: \frac{hb}{2} = A

[\frac{\sqrt{13}}{2}][\sqrt{13}] = \frac{13}{2} = 6\frac{1}{2} \\ \\ 6\frac{1}{2} = A

I am joyous to assist you anytime.

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