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3 years ago

Which statement describes the graph of the number of apples in the bag?

Mathematics

1 answer:

Sophie [7]3 years ago

7 0

Ello :) what was the answer? im taking this test ATM.

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When constructing parallel and perpendicular lines, how are the steps similar?

Rasek [7]

<span>Intersecting arcs are created and connected.</span>

6 0

2 years ago

What is the range of the function graphed below ?

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

I counted by recording all the numbers nd steps

7 0

2 years ago

Read 2 more answers

Use the remainder Theorem and synthetic division to find p(3) for p(x) = x4 + x3 -x2 - 2x

maxonik [38]

You do not need to use the remainder theorem to find p(3). Just plugin 3 where the x is located in

$x^4 + x^3 - x^2 - 2x$

$3^4 + 3^3 - 3^2 - 2(3) = 93$

Answer is a.

4 0

3 years ago

The authors of a paper presented a correlation analysis to investigate the relationship between maximal lactate level x and musc

ArbitrLikvidat [17]

Answer:

a) Sample correlation coefficient, r = 0.7411

bi) test statistic, t = 4.102

bii) P-value = 0.000736

Step-by-step explanation:

a) The formula for the sample correlation coefficient is given by the formula:

$r = \frac{S_{xy} }{\sqrt{S_{xx} S_{yy} }} }$

$S_{xx} = 2,648,130.357\\S_{yy} = 36.7376,\\S_{xy} = 7408.225$

$r = \frac{7408.225}{\sqrt{2648130.357*36.7376} }$

r = 0.7511

i) formula for the test statistic is given by the formula:

$t = \frac{r\sqrt{n-1} }{\sqrt{1 - r^{2} } }$

sample size, n = 4

$t = \frac{0.7511\sqrt{14-1} }{\sqrt{1 - 0.7511^{2} } }$

t = 4.102

ii) Degree of freedom, df = n -2

df = 14 -2

df = 12

The P-value is calculate from the degree of freedom and the test statistic using excel

P-value =(=TDIST(t,df,tail))

P-value = (=TDIST(4.1,12,1)

P-value = 0.000736

4 0

2 years ago

A certain radioactive isotope has leaked into a small stream. Three hundred days after the leak, 3% of the original amount of t

sesenic [268]

If the half-life is t, then every t days, the amount of the radioactive isotope will be cut in half.
(1/2)^(number of half-lives) = 3%
number of half-lives = ln(0.03) / ln(0.5)
This gives the number of half-lives as 5.06.
Then 300 days = (5.06)(length of 1 half-life)
length of 1 half-life = 300 / 5.06 = 59.29 days

6 0

3 years ago