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seraphim [82]
3 years ago
14

PLS HELP ME!!!!! IM TIMMED!!!!!!!

Chemistry
2 answers:
tresset_1 [31]3 years ago
7 0

Answer:

Where is the question?

Explanation:

Fynjy0 [20]3 years ago
6 0

Answer:

*Helps you*

Boom. ur helped

Explanation:

Brainly pwese

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If I have 4.5 liters of gas at a temperature of 33 0C and a pressure of 6.54 atm, what will be the pressure of the gas if I rais
Nikitich [7]

This is an exercise in the general or combined gas law.

To start solving this exercise, we must obtain the following data:

<h3>Data:</h3>
  • V₁ = 4.5 l
  • T₁ = 33 °C + 273 = 306 k
  • P₁ = 6.54 atm
  • T₂ = 94 °C + 273 = 367 k
  • V₂ = 2.3 l
  • P₂ = ¿?

We use the following formula:

  • P₁V₁T₂ = P₂V₂T₁ ⇒ General Formula

Where

  • P₁ = Initial pressure
  • V₁ = Initial volume
  • T₂ = Initial temperature
  • P₂ = Final pressure
  • V₂ = Final volume
  • T₁ = Initial temperature

We clear the general formula for the final pressure.

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2} }{V_{2}T_{1}}  \ \to \ Clear \ formula \end{gathered}$}

We solve by substituting our data in the formula:

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(6.54 \ atm)(4.5 \not{l})(367 \not{K}) }{(2.3 \not{l})(306 \not{k})}  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{10800.81}{ 703.8 } \ atm  \end{gathered}$}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=15.346 \ atm \end{gathered}$} }

If I raise the temperature to 94°C and decrease the volume to 2.3 liters, the pressure of the gas will be 15,346 atm.

8 0
2 years ago
Read 2 more answers
Water enters a 4.00-m3 tank at a rate of 6.33 kg/s and is withdrawn at a rate of 3.25 kg/s. The tank is initially half full.
olga55 [171]

Answer:

At the start of the process, the volume not occupied by the water is 2 m3

Explanation:

At the start of the process you have a half full tank. It means that also a half is empty (not occupied by water).

Since the volume is 4 m3, 2 m3 are full (occupied by water) and 2 m3 (not occupied by water).

The volume in time will be

V(t)=V_0+(f_i-f_o)*t\\\\V(t) = 2 +(6.33/1000-3.25/1000)*t=2+0.00308*t \, \, [m3]

8 0
3 years ago
2. Lithium-6 is 4% abundant and lithium-7 is 96% abundant. What is the average mass of lithium?
Lisa [10]

Answer:

Average atomic mass = 6.96 amu.

Explanation:

Abundance of Li-6 = 4%

Abundance of Li-7 = 96%

Atomic mass of Li-6 = 6 amu

Atomic mass of Li-7 = 7 amu

Average atomic mass = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (4×6)+(96×7) /100

Average atomic mass =  24 + 672 / 100

Average atomic mass = 696 / 100

Average atomic mass = 6.96 amu.

8 0
3 years ago
Coordination number of Nacl structure is ?​
GenaCL600 [577]

Answer:

Six

The coordination number of sodium is 6. Likewise, six sodium ions immediately surround each chloride ions, making the coordination number of chloride also equal to 6. Because the formula unit of sodium chloride displays a 1:1 ratio between the ions, the coordination numbers must be the same.

4 0
3 years ago
Read 2 more answers
When was the first published textbook containing a table identifying the first 33 elements
olya-2409 [2.1K]

1789 -- raité élémentaire de chimie is a textbook written by Antoine Lavoisier published in 1789 and translated into English by Robert Kerr in 1790 under the title Elements of Chemistry

5 0
3 years ago
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