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Novosadov [1.4K]
3 years ago
11

A proton moves at 5.20 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 8.40

103 N/C. Ignore any gravitational effects. (a) Find the time interval required for the proton to travel 4.50 cm horizontally.
Mathematics
1 answer:
lozanna [386]3 years ago
7 0

Answer:

  86.5 ns

Step-by-step explanation:

The speed in the original direction (horizontally) is unchanged by the vertical force the field exerts. The travel time is ...

  time = distance/speed = (4.5×10^-2 m)/(5.20×10^5 m/s) = 8.65×10^-8 s

_____

An engineer would express this time using the SI prefix nano- for 10^-9. The time is 86.5 ns.

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<em>Hello there, and thank you for asking your question here on brainly.

<u>Short answer: A. 1272 cm</u></em>³
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Why?

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4. How does the law of conservation of energy apply to the coal power plant?
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in a small machine shop, eight 5-gallon drums of oil are on hand. if 2 gallons are used each day and the owner wants a 30-day su
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3 years ago
A random sample of 20 purchases showed the amounts in the table (in $). The mean is $49.57 and the standard deviation is $20.28.
son4ous [18]

Answer:

The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.01 = 0.99, so z = 2.325

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The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

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3 years ago
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