How can you tell if a equation is extraneous

1 answer:

6 0

Do you mean an extraneous solution? I will tell you what I think. To tell if a solution is extraneous you need to go back to the original problem and check if there actually is a solution or if the solution is actually right. If not then it is extraneous.

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Find an equation for the nth term of the arithmetic sequence. <br> -3, -5, -7, -9, ...

tankabanditka [31]

Answer:

a(n) = -3 - 2(n-1)

Step-by-step explanation:

The most general formula for the nth term of an arithmetic sequence (such as this sequence is) is

a(n) = a(1) + c(n-1), where c is the common difference.

Here a(1) = -3 and c = -2.

Thus,

a(n) = -3 - 2(n-1).

7 0

2 years ago

Help answer asap pls ---------

Reika [66]

Answer:

d = 5

Step-by-step explanation:

We want to know what d would be when x = -1, so we can start off by plugging in -1 for x to get the following equation: $\sqrt{8 - (-1)} = 2(-1)+d$ . On the left hand side, 2 negatives become a positive sign, so the -(-1) becomes a +1, and 8+1 would equal 9. On the right hand side, we just multiply 2 and -1 to get -2. So, the equation now looks like this: $\sqrt{9} = d-2$ . We know that $\sqrt{9}$ = 3, so we would get 3 = d-2. THen we would add 2 to both sides to get d = 5. Hope this helps!