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3 years ago

Abby can buy an 8 pound bag of dog food for 7.40 or a 4 pound bag of the same dog food for 5.38 which is better buy

2 answers:

7 0

The 8 pound bag is a better deal8 Pound Bag8= 7.401= 0.92593 cents per pound
4 pound bag4= 5.381= 1.3451 dollar and 35 cents per pound
<span>The 8 pound bag is a better deal by 42 centers per pound </span>

mars1129 [50]3 years ago

6 0

The 8 pound bag is a better deal

8 Pound Bag

8= 7.40

1= 0.925

93 cents per pound

4 pound bag

4= 5.38

1= 1.345

1 dollar and 35 cents per pound

The 8 pound bag is a better deal by 42 centers per pound

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Which is equivalent to 10/12?options: 10/18 5/6 3/12 9/11

RideAnS [48]

Answer:

5/6 is equivalent to 10/12

Step-by-step explanation:

Hope this helped :)

7 0

3 years ago

4. two lines are perpendicular when

Gre4nikov [31]

c c a a are the right answers just took it

8 0

3 years ago

Read 2 more answers

How do I solve this question?

Sati [7]

Answer:

m=2 and n=3

Step-by-step explanation:

<u>Step</u> :-

Given $[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

using algebraic formula $(a^m)^n= a^{mn}$

now

$2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}$

now equating 'x' powers, we get

$x^{mn} = x^{6}$

$mn=6$ ....(1)

now

$y^{2m} = y^{4}$

Equating 'y' powers ,we get

2 m=4

m=2

substitute m= 2 in equation (1)

we get

2 n=6

n=3

verification:-

substitute m=2 and n=3 , we get

$[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

$(2 x^{3} y^2)^2 = 4 x^6 y ^4\\$

$4 x^6 y^4 = 4 x^6 y^4$

both are equating so m= 2 and n=3

4 0

3 years ago

A normal distribution has a standard deviation equal to 39. What is the mean of this normal distribution if the probability of s

Naily [24]

Answer:

The mean is $\mu = 131$

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\sigma = 39$