If the vertices of triangle bcd are B(-3,3) and c(3,5) and d(-1,0). what is the perimeter?
2 answers:
D ( BD ) = √( 2² + 3² ) = √(4+9) = √13 ≈ 3.61
d ( DC ) = √( 4² + 5² ) = √(16+25) = √41 ≈6.40
d ( CB ) = √( 6² + 2² ) = √(36+4) = √40 ≈ 6.32
The perimeter: 3.61 + 6.40 + 6.32 = 16.33
Answer:
C ) 16.33
Sorry i hit one star instead of five on helpful and now it wont let me change it! However, you are correct...the answer was C. Just took test. Thanks!
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