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Lera25 [3.4K]
4 years ago
5

If the vertices of triangle bcd are B(-3,3) and c(3,5) and d(-1,0). what is the perimeter?

Mathematics
2 answers:
Klio2033 [76]4 years ago
8 0
D ( BD ) = √( 2² + 3² ) = √(4+9) = √13 ≈ 3.61
d ( DC ) = √( 4² + 5² ) = √(16+25) = √41 ≈6.40
d ( CB ) = √( 6² + 2² ) = √(36+4) = √40 ≈ 6.32
The perimeter:  3.61 + 6.40 + 6.32 = 16.33
Answer:
C ) 16.33   
Olin [163]4 years ago
4 0

Sorry i hit one star instead of five on helpful and now it wont let me change it! However, you are correct...the answer was C. Just took test. Thanks!

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Answer:

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Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

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From the question the points are

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The distance between them is

d =  \sqrt{ ({5 + 7})^{2}  +  ({ - 5 - 4})^{2} }  \\  =  \sqrt{ {12}^{2}  + ( { - 9})^{2} }  \\  =  \sqrt{144 + 81}  \\  =  \sqrt{225}  \\  = 15 \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>15 units</h3>

Hope this helps you

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