The answer is x bc when you decreasing the interval f(x) it will equal (-2)
Answer:
55/43
Step-by-step explanation:
(x/y) = 7/3, (x^2/y^2)=49/9, multiply by 3 above and multiply 2 below, 3x^2/2y^2=147/18. Next apply C&D and you will get (3x^2+2y^2)/(3x^2-2y^2)=(147+18)/(147-18)=165/129=55/43
I just did it on paper but hope that helps:)
The diagonals of a parallelogram bisect each other.
DH = HF and GH = HE
x + 5 = 2y
3x - 1 = 5y + 4
Solve the first equation for x.
x = 2y - 5
Now substitute 2y - 5 for x in the second equation.
3(2y - 5) - 1 = 5y + 4
6y - 15 - 1 = 5y + 4
6y - 16 = 5y + 4
y = 20
Now substitute 20 for y in the first original equation.
x + 5 = 2y
x + 5 = 2(20)
x + 5 = 40
x = 35
Answer: x = 35 and y = 20
