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alex41 [277]
3 years ago
10

All of the following are examples of a heterogeneous mixture EXCEPT:

Chemistry
2 answers:
CaHeK987 [17]3 years ago
3 0
I think the answer is either a or d i haven't taken that class in awhile but if i were to pick one it would be D

GenaCL600 [577]3 years ago
3 0
D. Blood, because its not a heterogeneous mixture
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What is the total probability of finding a particle in a one-dimensional box in level n = 4 between x = 0 and x = L/8?
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Answer:

P = 1/8

Explanation:

The wave function of a particle in a one-dimensional box is given by:

\psi = \sqrt \frac{2}{L} sin(\frac{n \pi x}{L})

Hence, the probability of finding the particle in the  one-dimensional box is:

P = \int_{x_{1}}^{x_{2}} \psi^{2} dx

P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx

P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]

P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})    

Solving for n=4:

P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})    

P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})    

P = \frac{1}{8}

I hope it helps you!

7 0
3 years ago
Is carbon dioxide a iconic or covalent compound
igomit [66]
It is a covalant bond. Because any compound made up of nonmetals will be covalant. Compounds made up of a non metal and metal willl form a ionic compund. :)
3 0
3 years ago
Write a formula for the ionic compound that forms from magnesium<br> and oxygen.
Fed [463]

Answer:

MgO

Explanation:

8 0
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likoan [24]

Answer:

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Explanation:

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nignag [31]

Answer:

D

Explanation:

The resolution of a light microscope is approximately 200 nanometers due to the wavelength of light. A eukaryotic cell is approximately 1 – 5 micrometers. This means that light can be used to view a eukaryotic cell because the wavelength of light is smaller than the size of the cell. The other options are of a smaller size than the light wavelength and hence lower wavelength beams (such as those of electron microscope) or laser can be used to view them.

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4 years ago
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