Answer:
75
Explanation:
is the answer for your question
Answer:
485.76 g of CO₂ can be made by this combustion
Explanation:
Combustion reaction:
2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)
If we only have the amount of butane, we assume the oxygen is the excess reagent.
Ratio is 2:8. Let's make a rule of three:
2 moles of butane can produce 8 moles of dioxide
Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂
We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g
Answer:
1.0 x 10⁻⁸ M.
Explanation:
<em>∵ [H⁺][OH⁻] = 10⁻¹⁴.
</em>
∵ [H⁺] = 100 [OH⁻].
∴ 100 [OH⁻][OH⁻] = 10⁻¹⁴.
∴ 100 [OH⁻]² = 10⁻¹⁴.
[OH⁻]² = 10⁻¹⁴/ 100 = 1.0 x 10⁻¹⁶.
<em>∴ [OH⁻] = √(1.0 x 10⁻¹⁶) = 1.0 x 10⁻⁸ M.
</em>
