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Lorico [155]
2 years ago
15

The formula K₂S indicates that _______.

Chemistry
1 answer:
Pachacha [2.7K]2 years ago
5 0
The subscriot 2 means that in the formula there are two parts of K, and the subscript 1 (implicit) for S, indicates that there is one part of S.

This is, the formula gives the ratio of the elements K and S in the compound, which is:

2 atoms of K : 1 atom of S.

Answer: there are 2 atoms of K and 1 atom of S in a molecule of K2S.
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How strong are bonds between subatomic particles?
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Jason ran 5/7 of the distance around the school track sara ran 4/5 of Jason distance what fraction of the total distance around
FrozenT [24]
Let x represent the total distance around the track
Jason's distance: (5/7)x
Sara ran (4/5) of Jason's distance,
so she ran (4/5)*(5/7)x = (4/7)x
Sara ran 4/7 of the total distance
7 0
3 years ago
How does the presence of a catalyst affect the enthalpy of a reaction? Group of answer choices 1. It depends on whether you are
Otrada [13]

Answer:

Option 3. The catalyst does not affect the enthalpy change (\Delta H_\text{rxn}) of a reaction.

Explanation:

As its name suggests, the enthalpy change of a reaction (\Delta H_\text{rxn}) is the difference between the enthalpy of the products and the reactants.

On the other hand, a catalyst speeds up a reaction because it provides an alternative reaction pathway from the reactants to the products.

In effect, a catalyst reduces the activation energy of the reaction in both directions. The reactants and products of the reaction won't change. As a result, the difference in their enthalpies won't change, either. That's the same as saying that the enthalpy change \Delta H_\text{rxn} of the reaction would stay the same.

Refer to an energy profile diagram. Enthalpy change of the reaction \Delta H_\text{rxn} measures the difference between the two horizontal sections. Indeed, the catalyst lowered the height of the peak. However, that did not change the height of each horizontal section or the difference between them. Hence, the enthalpy change of the reaction stayed the same.

6 0
2 years ago
A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At
Mazyrski [523]
According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,

                                          P</span>₁ / T₁  =  P₂ / T₂     ----- (1)
Data Given;
                  P₁  =  1.5 atm

                  T₁  =  35 °C + 273  =  308 K

                  P₂  =  ?

                  T₂  =  0 °C + 273  =  273 K

Solving Eq. 1 for P₂,

                                   P₂  =  P₁ T₂ / T₁

Putting values,
                                   P₂  =  (1.5 atm × 273 K) ÷ 308 K

                                   P₂  =  1.32 atm
Result:
           As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.
5 0
3 years ago
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