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Lorico [155]
3 years ago
15

The formula K₂S indicates that _______.

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
5 0
The subscriot 2 means that in the formula there are two parts of K, and the subscript 1 (implicit) for S, indicates that there is one part of S.

This is, the formula gives the ratio of the elements K and S in the compound, which is:

2 atoms of K : 1 atom of S.

Answer: there are 2 atoms of K and 1 atom of S in a molecule of K2S.
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K2Te+ Fe(HCO3)2------&gt; KHCO3 + Fe Te<br> how do you balance the equation?
ololo11 [35]

Hey there!

K₂Te + Fe(HCO₃)₂ → KHCO₃ + Fe + Te

Start by balancing HCO₃ since it's a polyatomic ion.

Two on the left, one on the right. Add a coefficient of 2 in front of KHCO₃.

K₂Te + Fe(HCO₃)₂ → 2KHCO₃ + Fe + Te

Balance K .

Two on the left, two on the right. Already balanced.

Balance Te.

One on the left, one on the right. Already balanced.

Balance Fe.

One on the left, one on the right. Already balanced.

Our final balanced equation:

K₂Te + Fe(HCO₃)₂ → 2KHCO₃ + Fe + Te

Hope this helps!

4 0
3 years ago
Below are shown, for five metals, reduction reactions and standard electrode potential values. which of these metals is the leas
just olya [345]
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.

In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.

On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive. 


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