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Lorico [155]
3 years ago
15

The formula K₂S indicates that _______.

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
5 0
The subscriot 2 means that in the formula there are two parts of K, and the subscript 1 (implicit) for S, indicates that there is one part of S.

This is, the formula gives the ratio of the elements K and S in the compound, which is:

2 atoms of K : 1 atom of S.

Answer: there are 2 atoms of K and 1 atom of S in a molecule of K2S.
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It takes 16.02 days for the activity of Y90

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles  

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

No=192 μCi

Nt=3 μCi

t1/2=2.67 days

\tt 3=192(\dfrac{1}{2})^{\dfrac{T}{2.67}}\\\\\dfrac{1}{64}=\dfrac{1}{2}^{\dfrac{T}{2.67}}\\\\\dfrac{1}{2}^6=\dfrac{1}{2}^{\dfrac{T}{2.67}}\\\\6=\dfrac{T}{2.67}\\\\T=16.02~days

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Which one of the following is not a compound?
Studentka2010 [4]
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The percent ionization of a 0.350 M HC,H,O2 solution. Ka(HC2H302)​
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Which characteristics show that large herbivores are adapted to the taiga?
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3

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3 0
3 years ago
Read 2 more answers
Example 1: urea, (nh2)2co, is used in the manufacture of resins and glues. when 5.00 g of urea is dissolved in 250.0 ml of water
katen-ka-za [31]
A) i believe the reaction is exothermic, because 27.6 kg of thermal energy is gained by the water solution, the dissolution of urea is exothermic. Exothermic reaction is a chemical reaction that releases energy by light or heat. It is the opposite of an endothermic reaction where heat is gained by the reaction.

b) The water gained the heat released when urea dissolve. That is the water gained 27.6 kJ, while dissolution of urea released 27.6 kJ. Therefore, the heat gained is equal to the heat lost.

c) From part B, since heat gained is equal to heal lost, then
250 g × (Tf -30) ×4.18 J/g = 27600 J
 = 1045 Tf - 31350J = 27600 J
Tf = 56.41°C.
Therefore the final temperature  of the solution is 56.41°C

d) The initial and final temperature in Fahrenheit
°F = °C × (9/5) +32,
Thus, 30°C will be equal to 86° F
while 56.41 will be equivalent to  133.54 ° F


7 0
3 years ago
Read 2 more answers
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