Hey there!
K₂Te + Fe(HCO₃)₂ → KHCO₃ + Fe + Te
Start by balancing HCO₃ since it's a polyatomic ion.
Two on the left, one on the right. Add a coefficient of 2 in front of KHCO₃.
K₂Te + Fe(HCO₃)₂ → 2KHCO₃ + Fe + Te
Balance K .
Two on the left, two on the right. Already balanced.
Balance Te.
One on the left, one on the right. Already balanced.
Balance Fe.
One on the left, one on the right. Already balanced.
Our final balanced equation:
K₂Te + Fe(HCO₃)₂ → 2KHCO₃ + Fe + Te
Hope this helps!
Above question is incomplete. Complete question is attached below
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Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.
In present case,
reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is
least reactive.
On other hand,
reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is
most reactive.
Answer:
the eye of the tiger in the bronx zoo tiger king meme with
The axon is a thin fiber that carries signals away from the cell body.
I believe it is BaS I hope this helps!