All categories

3 years ago

Whats is not a characteristic of the eye of a hurricane

Chemistry

2 answers:

lukranit [14]3 years ago

7 0

B.has the storms strongest winds

Marina86 [1]3 years ago

5 0

B. has the storms strongest winds is not a characteristic of the eye of a hurricane because in the eye it is actually completely calm.

Hope that helps u!!

You might be interested in

The solubility of in water at a certain temperature is 35.7 g /100. g . Suppose that you have 330.0 g of . What is the minimum v

juin [17]

The question is incomplete, here is the complete question:

The solubility of substance X in water at a certain temperature is 35.7 g /100. g. Suppose that you have 330.0 g of substance X. What is the minimum volume of water you would need to dissolve it all? (Assume that the density of water is 1.00 g/mL.)

Answer: The minimum volume of water that would be needed is 940.17 mL

Explanation:

We are given:

Solubility of substance X in water = 35.1 g/100 g

This means that 35.1 grams of substance X is dissolved in 100 grams of water

Applying unitary method:

If 35.1 grams of substance X is dissolved in 100 grams of water

So, 330.0 grams of substance X will be dissolved in = $\frac{100}{35.1}\times 330=940.17g$ of water

To calculate the volume of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Mass of water = 940.17 g

Putting values in above equation, we get:

$1g/mL=\frac{940.17g}{\text{Volume of water}}\\\\\text{Volume of water}=\frac{940.17g}{1g/mL}=940.17mL$

Hence, the minimum volume of water that would be needed is 940.17 mL

8 0

3 years ago

A solution is prepared from 26.7 g of an unknown compound and 116.2 g acetone, C3H6O, at 313 K. At this temperature the vapor pr

Cloud [144]

Answer:

The molecular weight of the unknown compound is 267.7 g/mol

Explanation:

Lowering vapor pressure → Colligative property where the vapor pressure of solution is lower than vapor pressure of pure solvent

ΔP = P° . Xm

0.526 atm - 0.501 atm = 0.025atm

0.025 atm = 0.526 atm . Xm

Xm = 0.025 atm / 0.526 atm → 0.0475 (mole fraction)

Mole fraction = Moles of solute / Total moles (solute + solvent)

0.0475 = Moles of solute / Moles of solute + Moles of solvent

We determine the moles of solvent → 116.2 g . 1mol / 58 g = 2 moles

0.0475 = Moles of solute / Moles of solute + 2

0.0475 moles of solute + 0.095 = Moles of solute

0.095 = Moles of solute - 0.0475 moles of solute

0.095 / 0.9525 = Moles of solute → 0.0997 moles

Molas mass = g/mol → 26.7 g / 0.0997 mol = 267.7 g/mol

4 0

2 years ago

What families do you have in your chart

Vladimir79 [104]

Answer:

Families in chart is offsprings made from molecules

Explanation:

Because babies are made from the offspring on which your eye colors,hair colors and etc.

3 0

2 years ago

A party balloon contains 5.50 x 10 ^22 atoms of helium gas. What is the mass, in grams of the

eduard

Answer:

$\boxed {\boxed {\sf A. \ 0.365 \ g\ He}}$

Explanation:

1. Convert Atoms to Moles

We must use Avogadro's Number: 6.022*10²³. This is the number of particles (atoms, molecules, ions, etc.) in 1 mole of a substance. In this case, the particles are atoms of helium. We can create a ratio.

$\frac {6.022*10^{23} \ atoms \ He}{1 \ mol \ He}$

Multiply by the given number of helium atoms.

$5.50 *10^{22} \ atoms \ He *\frac {6.022*10^{23} \ atoms \ He}{1 \ mol \ He}$

Flip the fraction so the atoms of helium cancel.

$5.50 *10^{22} \ atoms \ He *\frac {1 \ mol \ He}{6.022*10^{23} \ atoms \ He}$

$5.50 *10^{22} *\frac {1 \ mol \ He}{6.022*10^{23} }$

$\frac {5.50 *10^{22} \ mol \ He}{6.022*10^{23} }= 0.09133178346 \ mol \ He$

2. Convert Moles to Grams

We must use the molar mass, which is found on the Periodic Table.

Helium (He): 4.00 g/mol

Use this as a ratio.

$\frac { 4.00 \ g \ He }{ 1 \ mol \ He}$

Multiply by the number of moles we calculated. The moles will then cancel.

$0.09133178346 \ mol \ He *\frac { 4.00 \ g \ He }{ 1 \ mol \ He}$

$0.09133178346*\frac { 4.00 \ g \ He }{ 1 }$

$0.3653271338 \ g\ He$

3. Round

The original measurement has 3 significant figures (5, 5, and 0). Our answer must have the same. For the number we calculated, it is thousandth place. The 3 in the ten thousandth place tells us to leave the 5.

$0.365 \ g\ He$

The mass is 0.365 grams of helium so choice A is correct.

7 0

2 years ago

What will most likely happen if a sound wave moves from the air through a solid?

Alchen [17]

The wavelength of the associated sound will increase. This will be noticed by the sound having a lower tone. As the sound passes through the solid object, not only will it sound lower in tone, it will sound softer, evidenced by if a person closes a door to a room and listens to a sound played from inside.

7 0

2 years ago

Read 2 more answers