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lawyer [7]
3 years ago
10

Write a formula for the ionic compound that forms from magnesium and oxygen.

Chemistry
1 answer:
Fed [463]3 years ago
8 0

Answer:

MgO

Explanation:

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3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
Morgarella [4.7K]

Answer:

Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

Thus, the total number of molecules turns out:

Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec

Regards.

6 0
3 years ago
One mole of H atom is equal to
valentina_108 [34]
16 grams I think it might be it
6 0
3 years ago
Why methylene blue is blue
bixtya [17]

Methylene blue indicates the presence of oxidizing agents because it is oxidized itself by these compounds. When electrons are stripped from methylene blue, the resulting molecule imparts a blue color to the solution--giving a clear sign of a chemical change.

7 0
3 years ago
PLEASEEEE HELP I WILL MARK YOU BRAINIEST!!!!
Tju [1.3M]

Answer:

sorry i dont know the answer but i hope you can figure it out soon

5 0
3 years ago
How much energy will it take to raise the temperature of 75.0 g of water from 20.0°C to 55.0°C?
Hatshy [7]

Answer:

We can use heat = mcΔT to determine the amount of heat, but first we need to determine ΔT. Because the final temperature of the water is 55°C and the initial temperature is 20.0°C, ΔT is as follows:

ΔT = Tfinal − Tinitial = 55.0°C − 20.0°C = 35.0°C

given the specific heat of water as 1 cal/g·°C. Substitute the known values into heat = mcΔT and solve for amount of heat:

=  heat=(75.0 g)(1 cal/ g· °C )(35.0°C) =

= 75x1x35=2625 cal

6 0
3 years ago
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