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3 years ago

6

6(y+4)^2-5=49

1 answer:

Marina86 [1]3 years ago

7 0

☾Let's solve this problem Step-By-Step!<span>☽</span>
☾Question you asked:
<span><span>6<span><span>(<span>y+4</span>)^</span>2</span></span>−5</span>=49

☾<span>Simplify both sides of the equation:
</span><span><span><span>6<span>y^2</span></span>+<span>48y</span></span>+91</span>=<span>49
</span>
☾<span>Subtract 49 from both sides:
</span><span><span><span><span>6<span>y^2</span></span>+<span>48y</span></span>+91</span>−49</span>=<span>49−49
</span><span><span><span>6<span>y^2</span></span>+<span>48y</span></span>+42</span>=<span>0
</span>
☾<span>Factor left side of equation:
</span><span><span>6<span>(<span>y+1</span>)</span></span><span>(<span>y+7</span>)</span></span>=<span>0
</span>
☾<span>Set factors equal to 0:
</span><span><span>y+1</span>=<span><span><span>0<span> or </span></span>y</span>+7</span></span>=<span>0
</span>
☾Your answer is:
<span>y=<span>−<span><span>1<span> or </span></span>y</span></span></span>=<span>−7
</span>
☾I hope this helps!☽

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