Answer:
ax² + bx + c
Step-by-step explanation:
The form of a quadratic equation that is easy to use when finding the maximum or minimum value of the function is ax² + bx + c.
Suppose a quadratic function:
f(x) = 2x² - 8x + 9
Use ( -b/2a , f(-b/2a) ).
-b/2a
a = 2
b = -8
-(-8)/2(2)
8/4
= 2
f(2) = 2(2)² - 8(2) + 9
f(2) = 2(4) - 8(2) + 9
f(2) = 8 - 16 + 9
f(2) = 1
The minimum value of this quadratic function is (2, 1).
It represents a minimum value because a > 0.
Answer:
x-intercept: (6,0)
y-intercept: (0,4)
Step-by-step explanation:
The x-intercepts lay on the x-axis and therefore their y-coordinate is 0.
To find the x-intercept, you set y to 0 and solve for x.
2x+3y=12
Set y=0.
2x+3(0)=12
2x+0 =12
2x =12
Divide both sides by 2:
x =12/2
x =6
The x-intercept is (x,y)=(6,0).
The y-intercepts lay on the y-axis and therefore their x-coordinate is 0.
To find the y-intercept, you set x to 0 solve for y.
2x+3y=12
2(0)+3y=12
0+3y =12
3y =12
Divide both sides by 3:
y =12/3
y =4
The y-intercept is (0,4).
Answer: uhh
Step-by-step explanation:
I really don’t know how to do it.