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murzikaleks [220]
3 years ago
12

The radius of circle C is 6 units and the measure of central angle ACB is StartFraction pi Over 2 EndFraction radians. What is t

he approximate area of the entire circle? square units What is the approximate area of the entire sector created by central angle ACB? square units What is the approximate area of the shaded region only? square units
edit- the answer is 140
Mathematics
2 answers:
monitta3 years ago
6 0

Answer:

Given: The radius of circle C is 6 units and the measure of central angle ACB is StartFraction pi Over 2 EndFraction radians.

What is the approximate area of the entire circle?

113 square units

What is the approximate area of the entire sector created by central angle ACB?

28 square units

What is the approximate area of the shaded region only?

22 square units

emmainna [20.7K]3 years ago
6 0

Answer:

113

28

22

Step-by-step explanation:

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3 years ago
A rectangular swimming pool that is 10 ft wide by 16 ft long is surrounded by a cement sidewalk of uniform width. If the area of
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5 0
3 years ago
A study was conducted to determine if the salaries of elementary school teachers from two neighboring districts were equal. A sa
Semenov [28]

Answer:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

(–2975, 175)

Do not reject H₀

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the salaries of elementary school teachers are equal in two districts. You can test this trough the population means of the salaries of the teachers if they are either equal or different or directly test if the difference between the salaries of the two districts is cero or not, symbolically: μ₁ - μ₂ = 0

Remember, in the null hypothesis is usually stated the known information, is the "no change" premise and always carries the = symbol.

The hypothesis is:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

You have two normally distributed variables and you are studying the difference of the means. You can use a pooled Z to make the interval, the formula is:

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Since the test is two-tailed and at a signification level of 5% I've made the interval at the complementary confidence level of 95% so that I can use it to decide over the hypothesis.

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Z_{1-\alpha /2} = Z_{0,975} = 1,96

[28900-30300 ± 1.96*(√((2300)²/15+(2100)²/15)]

[-1400 ± 1576,15]

[-2976.15;176,15]

Since I've approximated to two decimal units in the intermediate calculations, the values ​​differ slightly, but the interval is:

(–2975, 175)Now, since the 0 is contained in the Confidence interval, the decision is to not reject the null hypothesis. In other words, the difference in average salaries between the two districts is cero.

I hope it helps!

4 0
3 years ago
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