The radius of circle C is 6 units and the measure of central angle ACB is StartFraction pi Over 2 EndFraction radians. What is t
2 answers:
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We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.
The value of x is <span>5 feet. </span>
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.
The value of x is <span>5 feet. </span>
Answer:
H₀: μ₁ - μ₂ = 0
H₁: μ₁ - μ₂ ≠ 0
(–2975, 175)
Do not reject H₀
Step-by-step explanation:
Hello!
The objective of this experiment is to test if the salaries of elementary school teachers are equal in two districts. You can test this trough the population means of the salaries of the teachers if they are either equal or different or directly test if the difference between the salaries of the two districts is cero or not, symbolically: μ₁ - μ₂ = 0
Remember, in the null hypothesis is usually stated the known information, is the "no change" premise and always carries the = symbol.
The hypothesis is:
H₀: μ₁ - μ₂ = 0
H₁: μ₁ - μ₂ ≠ 0
You have two normally distributed variables and you are studying the difference of the means. You can use a pooled Z to make the interval, the formula is:
X[bar]₁-X[bar]₂ ± *(√(σ₁²/n₁+σ₂²/n₂)
Since the test is two-tailed and at a signification level of 5% I've made the interval at the complementary confidence level of 95% so that I can use it to decide over the hypothesis.
X[bar]₁-X[bar]₂ ± *(√(σ₁²/n₁+σ₂²/n₂)
=
= 1,96
[28900-30300 ± 1.96*(√((2300)²/15+(2100)²/15)]
[-1400 ± 1576,15]
[-2976.15;176,15]
Since I've approximated to two decimal units in the intermediate calculations, the values differ slightly, but the interval is:
(–2975, 175)Now, since the 0 is contained in the Confidence interval, the decision is to not reject the null hypothesis. In other words, the difference in average salaries between the two districts is cero.
I hope it helps!