6th grade fractions...
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Answer:
Area Of a Right Angled∆
=><em><u> </u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>x </u></em><em><u>Base </u></em><em><u>x </u></em><em><u>Height</u></em>
Area of a ∆ Using Heron's Formula
=>
Where
- S = Semiperimeter
- a ,b& c = sides of the ∆
It's a quadratic so the parent function will be
We can see that it has been shifted to the right 5 units, which gives us a new function
It has also been shifted up 9 units:
But it has also been flipped across the y-axis which makes this the final change we need to do:
We can see that it has been shifted to the right 5 units, which gives us a new function
It has also been shifted up 9 units:
But it has also been flipped across the y-axis which makes this the final change we need to do:
The solution of the equation (√x-8) + 2 = 7 is x = 13.
According to the given question.
We have an equation
Since, we solve the above equation for x .
Therefore,
⇒ (√x - 8) = 7 - 2
⇒ (√x - 8) = 5
Squarring both the sides.
⇒ x - 8 = 5
⇒ x = 5 + 8
⇒ x = 13
Hence, the solution of the equation (√x-8) + 2 = 7 is x = 13.
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