It has to be the 2 and 3 because when you multiply fractions you use keep change flip for example 2/3 divided by 2/3 you keep the first fraction 2/3 you change division to multiplication and you flip the last fraction which will be 2/3x3/2
I'm solving your system by substitution.
2x-4=5, 5x+4y =2
Step# 1: solve for x
2x - 4+ 4= 5 + 4( add +4 to both sides)
2x = 9
x = 9/2
Step# 2: solve for y
5(9/2) + 4y = 2
4y + 45/2 = 2
4y 45
y = 45/4 = 11.25
Dannng I thought I seen this one before
Solution
For this case we can do the following:
11y - 3x = 18
16y -3x = 33
We can multiply the first equation by -1 and we got:
-11y +3x =-18
16y -3x = 33
_______________
16y -11y = 33-18
5y = 15
y= 15/5 = 3
And then solving for x we got
x = -(18 -11*3)/ 3= -15/3 = 5
Answer:
x = 3/2 or x = -5/4
Step-by-step explanation:
Solve for x over the real numbers:
8 x^2 - 2 x - 15 = 0
Using the quadratic formula, solve for x.
x = (2 ± sqrt((-2)^2 - 4×8 (-15)))/(2×8) = (2 ± sqrt(4 + 480))/16 = (2 ± sqrt(484))/16:
x = (2 + sqrt(484))/16 or x = (2 - sqrt(484))/16
Simplify radicals.
sqrt(484) = sqrt(4×121) = sqrt(2^2×11^2) = 2×11 = 22:
x = (2 + 22)/16 or x = (2 - 22)/16
Evaluate (2 + 22)/16.
(2 + 22)/16 = 24/16 = 3/2:
x = 3/2 or x = (2 - 22)/16
Evaluate (2 - 22)/16.
(2 - 22)/16 = -20/16 = -5/4:
Answer: x = 3/2 or x = -5/4
