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kifflom [539]
3 years ago
11

Find the probability of drawing a green card, not replacing it, and then drawing another green card.

Mathematics
1 answer:
IRISSAK [1]3 years ago
7 0

Answer:

1/15

Step-by-step explanation:

This is probably too late but I'll do it anyway.

There are 10 cards in all.

of the 10, 3 are green.

So your chance of drawing the first green is 3/10

Now you have 9 cards in total left.

Two of them are green

Your chance of drawing a green card again is 2/9

Your total chance of drawing 2 green cards is

2/9 * 3/10 = 6/90

2/9 * 3/10 = 1/15

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Tex's Taco Truck serves tacos on either hard or soft shells. Yesterday, Tex's Taco Truck sold 5 hard-shell tacos for every 2 sof
Nady [450]

Answer:

65 hard-shells

26 soft shells

Step-by-step explanation:

5 x 13 = 65

2 x 13 = 26

65 - 26 = 39

7 0
3 years ago
Determine whether the set of all linear combinations of the following set of vector in R^3 is a line or a plane or all of R^3.a.
Temka [501]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix  ⇒

\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right]

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

4 0
3 years ago
PLZ PLZ PLZ ANSWER CORRECTLY IN A HERRY!!!!!
garri49 [273]
I think the answer is 16
5 0
3 years ago
Read 2 more answers
Solve the equation Square root of x minus 5+ 7 = 11 for the variable. Show each step of your solution process. (10 points)
Fed [463]
The opposite of square root is simply square, so try squaring both sides and use algebra
5 0
3 years ago
Please help! Thanks!
Ede4ka [16]
-9(6m-3)+6(1+4m)
=54m+27+6(1+4m)
=54m+27+6+24m
= -30m+33

5 0
3 years ago
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