Answer:
Decompositon
Explanation:
Sodium chlorate → Sodium Chloride + Oxygen
Sodium chlorate is reactant.
Sodium chloride + Oxygen is the product.
Definition : -
Decomposition reaction is a chemical reaction in which a single reactant breaks down to simpler products.
<u>Answer:</u> The concentration of reactant after the given time is 0.0205 M
<u>Explanation:</u>
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = 
t = time taken for decay process = 11.0 min = 660 s (Conversion factor: 1 min = 60 s)
= initial amount of the reactant = 0.400 M
[A] = amount left after decay process = ?
Putting values in above equation, we get:
![4.50\times 10^{-3}s^{-1}=\frac{2.303}{660s}\log\frac{0.400}{[A]}](https://tex.z-dn.net/?f=4.50%5Ctimes%2010%5E%7B-3%7Ds%5E%7B-1%7D%3D%5Cfrac%7B2.303%7D%7B660s%7D%5Clog%5Cfrac%7B0.400%7D%7B%5BA%5D%7D)
![[A]=0.0205M](https://tex.z-dn.net/?f=%5BA%5D%3D0.0205M)
Hence, the concentration of reactant after the given time is 0.0205 M
The answer is waterspouts
LAw of conservation of Energy is an important concept to solve this problem. The energy released is equal to the energy absorbed.
Ice undergoes latent heat. MEaning there is a change in phase but not temperature and the energy is solved by (enthalpy of fusion)(mass) = 333.5J/g)(8.5g). =2834.75J.
This is equal to the energy released by the water. The energy is computed by (mass)(specific heat of water)(temperature change) = (255g)(4.16J/gK)(T)
Final equation is:
2834.75 = 255(4.16)(T)
T = 2.67K
Molality is defined as the number of moles of solute in 1 kg of solvent.
molality of solution to be prepared is 0.50 molal
this means that in 1000 g of water there should be 0.50 mol of NaCl
if 1000 g of water should contain - 0.50 mol
then 750.0 g of water requires - 0.50 mol/kg x 0.750 kg = 0.375 mol
mass of NaCl in 0.375 mol - 58.5 g/mol x 0.375 mol = 21.9 g
therefore a mass of 21.9 g of NaCl is required