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3 years ago

What are the seven identified components of the electromagnetic spectrum?

Chemistry

2 answers:

NeTakaya3 years ago

7 0

Answer:

The EM spectrum is generally divided into seven regions, in order of decreasing wavelength and increasing energy and frequency. The common designations are: radio waves, microwaves, infrared (IR), visible light, ultraviolet (UV), X-rays and gamma rays.

Explanation:

Grace [21]3 years ago

5 0

Answer:

The EM ( electromagnetic) spectrum is generally divided into seven region ,in order of decreasing wave length and increasing energy and frequency.The common designations are:

1. Radio waves

2. Microwave

3. Infrared (IR).

4. Visible light.

5. Ultraviolet (UV).

6. X-rays.

7. Gamma rays.

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Question 2 of 50

wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

Write the balanced chemical equation for the given reaction.
Convert the mass of calcium carbonate into moles.
Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

$CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}$

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

$mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}$

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

$mol \ CaO \ = 0.2498 \ mol$

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

$mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g$

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

$\boxed {mass \ CaO \ = 14 \ g}$

Learn More

Learn more about stoichiometry brainly.com/question/12979299
Learn more about mole conversion brainly.com/question/12972204
Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

5 0

3 years ago

When the equation ZnS+O ZnO+SO isbalanced the coefficientof O is 1, 5, 3,or2

Flauer [41]

ZnS + O --> ZnO + SO

Okay so first you have to count up the number of elements on each side of the equation. Your objective is to have the same number of each element on both sides.

Left Side:
Zn - 1
S - 1
O - 1

Right Side:
Zn - 1
S - 1
O - 2

Since there are two oxygens on the right side, you have to add a coefficient of 2 to the oxygen on the left side. The coefficient tells us that that element or molecule is being multiplied by the value of coefficient. Since we're adding a coefficient of 2 to the oxygen on the left side, there are now 2 oxygens on that side. Because that is the same amount of oxygen as on the right, the equation is now balanced.

Your final equation should look like this: ZnS + 2O --> ZnO + SO

In conclusion, the answer is 2.

3 0

3 years ago

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Please help me i will give brain list

Strike441 [17]

Answer:

Give me plz plz plz plz plz plz plz plz plz

3 0

3 years ago

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Which one of the following statements is correct.

k0ka [10]

B. electrons have a negative electrical charge

7 0

3 years ago

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Can the excess reactant control the percentage yield? Please answer

Marina CMI [18]

Answer:

Yes, it can.

Explanation:

The percentage yield is decreased if the reactants do not completely form the products. To make a given mass of product, a process with a low percentage yield requires more of the reactants than a process with high percentage yield.

5 0

3 years ago

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