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Norma-Jean [14]
3 years ago
9

At a real estate agency, an agent sold a house for $311,000. The commission rate is 4.6% for the real

Mathematics
1 answer:
deff fn [24]3 years ago
4 0

9514 1404 393

Answer:

  • agency: $14,306
  • agent: $3,576.50

Step-by-step explanation:

The agency's commission was ...

  0.046 × $311,000 = $14,306

The agent's commission was ...

  0.25 × $14,306 = $3,576.50

__

The agency made $14,306; the agent earned $3,576.50.

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Simplify the expression below. 2x - 10 + 6x
PtichkaEL [24]

Answer:

8x - 10

Step-by-step explanation:

Combine like terms:

2x + 6x - 10

= 8x -10

4 0
3 years ago
Read 2 more answers
(the stake is 14ft)
Kaylis [27]

Answer:

it‘s about

32.08 ft (if its not an answer choice try 32 or anywhere near that number)

Step-by-step explanation:

SO this is a simple example of triangles

We would need to find the heigh of the flagpole which is the leg of the triangle

The other side (14ft) is the 2nd leg of the triangle

And we know the hypotenuse is 35 ft

So we put that in Pythagorean Theroux and solve for the first missing leg

a^2+14^2=35^2

a^2+196=1225

a^2=1029

√1029 is about 32.08

So its about 32.08

5 0
3 years ago
WHAT THE HECC IS THIS
anyanavicka [17]

Answer:

h(x)

Step-by-step explanation:

to solve for an inverse, you swap the x and the y and then solve for y

f(x) = 4x^3-8

y = 4x^3 - 8

x = 4y^3 - 8   swap the x and y

now solve for y:

x + 8 = 4y^3

(x + 8)/4 = y^3

1/4x + 8/4 = y^3

1/4x + 2 = y^3

y = \sqrt[3]{1/4x + 2}

4 0
2 years ago
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
 
Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
For the experiment described, write the indicated event in set notation.
pentagon [3]

Answer:

d. {(1,2),(2,2),(3,2),(4,2),(5,2),(6,2)}

Step-by-step explanation:

First one can be any of the six outcomes

7 0
4 years ago
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